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Tanya [424]
3 years ago
7

Use formulas to find the lateral and surface are of the given prism the numbers are 5.39m 26m 5m 2m 

Mathematics
2 answers:
MrMuchimi3 years ago
8 0
3(24) + 2(24) + 5.39(24) = 72 + 48 + 129.36 = 249.36 ~ 249m^2 

<span>Total Surface Area: </span>
<span>(add to the above) </span>
<span>2(1/2)(3)(2) = 6m^2 (area of the two triangles) </span>
<span>6 + 149 = 155m^2 </span>
nydimaria [60]3 years ago
8 0
The correct answer is <span>6 + 149 = 155m^2! Hope This Helps!
</span>
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Write a formula for a line that passes through the point (x,y) = (-3,5) and has an undefinedslopes.
Vladimir [108]

A line with undefined slope has an equation  x=a.

So,  for a line that passes through the point (x,y) = (-3,5) ,

has the equation x= - 3.

5 0
3 years ago
What is the perimeter of triangle ABC ?
blagie [28]

Answer:

9+\sqrt{41}

Step-by-step explanation:

From C-A, it goes from y=1 to y=5, so that 4 units

From A-B, it goes from x = -1 to x = 4, that is 5 units

Now, to find distance from B to C, we need to use the distance formula:

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Where the variables are the respective points of B and C,

B (4,5) & C(-1,1)

So x_1 =4, y_1=5, x_2=-1, y_2=1

Plugging into the formula we get:

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\D=\sqrt{(1-5)^2+(-1-4)^2}\\D=\sqrt{16+25}\\ D=\sqrt{41}

Summing it all (perimeter is sum of 3 sides):

Distance = 4+5+\sqrt{41}\\ =9+\sqrt{41}

3rd answer choice is right.

3 0
3 years ago
Which coefficient matrix represents a system of linear equations that has a unique solution ?
finlep [7]

Answer:

Option C

Step-by-step explanation:

We are given a coefficient matrix along and not the solution matrix

Since solution matrix is not given we cannot check for infinity solutions.

But we can check whether coefficient matrix is 0 or not

If coefficient matrix is zero, the system is inconsistent and hence no solution.

Option A)

|A|=\left[\begin{array}{ccc}4&2&6\\2&1&3\\-2&3&-4\end{array}\right] =0

since II row is a multiple of I row

Hence no solution or infinite

OPtion B

|B|=\left[\begin{array}{ccc}2&0&-2\\-7&1&5\\4&-2&0\end{array}\right] \\=2(10)-2(10)=0

Hence no solution or infinite

Option C

\left[\begin{array}{ccc}6&0&-2\\-2&0&6\\1&-2&0\end{array}\right] \\=2(36-2)=68

Hence there will be a unique solution

Option D

\left[\begin{array}{ccc}5&10&5\\4&1&4\\-1&-2&-1\end{array}\right] \\=2(10)-2(10)=0=0

(since I row is -5 times III row)

Hence there will be no or infinite solution

Option C is the correct answer



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