13) 120 + 1.5 + 0.25 = 121.75 pounds
14) 4 - 1.5 = 2.5 pints
15) (2.25)(32)= $72
Martin still has 30% of the problems left to do.
The vector i=<1,0> and j=<0,1> so the i+j=<1+0,0+1>=<1,1>. The length of this vector is easy: |i+j|=<span>2–√</span>
to make the vector i+j=<1,1> a unit vector we rescale it by it's
length (i.e. divide i+j by its length) , v=(i+j)/(|i+j|)
thus we have v=<span>1/<span>2–√</span><1,1></span> or <span><1/<span>2–√</span>,1/<span>2–√</span>></span>
If you check the length of this vector v, you see it indeed does have
length =1. It is parallel to the vector i+j because it's components are
proportional to the components of i+j=<1,1>.
Answer:
The Proof for
Part C , Qs 9 and Qs 10 is below.
Step-by-step explanation:
PART C .
Given:
AD || BC ,
AE ≅ EC
To Prove:
ΔAED ≅ ΔCEB
Proof:
Statement Reason
1. AD || BC 1. Given
2. ∠A ≅ ∠C 2. Alternate Angles Theorem as AD || BC
3. ∠AED ≅ ∠CEB 3. Vertical Opposite Angle Theorem.
4. AE ≅ EC 4. Given
5. ΔAED ≅ ΔCEB 5. By A-S-A congruence test....Proved
Qs 9)
Given:
AB ≅ BC ,
∠ABD ≅ ∠CBD
To Prove:
∠A ≅ ∠C
Proof:
Statement Reason
1. AB ≅ BC 1. Given
2. ∠ABD ≅ ∠CBD 2. Given
3. BD ≅ BD 3. Reflexive Property
4. ΔABD ≅ ΔCBD 4. By S-A-S congruence test
5. ∠A ≅ ∠C 5. Corresponding parts of congruent Triangles Proved.
Qs 10)
Given:
∠MCI ≅ ∠AIC
MC ≅ AI
To Prove:
ΔMCI ≅ ΔAIC
Proof:
Statement Reason
1. ∠MCI ≅ ∠AIC 1. Given
2. MC ≅ AI 2. Given
3. CI ≅ CI 3. Reflexive Property
4. ΔMCI ≅ ΔAIC 4. By S-A-S congruence test
Answer:
Step-by-stepMONNKKKKKK explanation: