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3 years ago

20-(6x4)+10+(9x3)-4=

Mathematics

2 answers:

Murljashka [212]3 years ago

8 0

Answer:

$29$

Step-by-step explanation:

$20-(6 \times 4)+10+(9 \times 3)-4$

$20-(24)+10+(27)-4$

$20-24+10+27-4$

$10+27+20-24-4$

$57-28$

$=29$

nevsk [136]3 years ago

7 0

Answer:

Step-by-step explanation:

20-(6×4)+10+(9×3)-4=

20-24+10+27-4=

-4+10+27-4=

6+27-4=

33-4=

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(8+3i)+(-6-12i) quadratic equation simplified.

ASHA 777 [7]

Simplified answer would be 2 - 9i.

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3 years ago

Please please help! I'm stuck on this

Phantasy [73]

Answer:

A'(-4 , 10)

B'(-4, 12)

C'(0, 12)

D'(0, 10)

Step-by-step explanation:

Given in the question are 4 coordinates of Quadrilateral ABCD

A(−2, 2)

B(−2, 4)

C(2, 4)

D(2, 2)

The rule is (x − 2, y + 8), that means

the translation is 2 units to the left and 8 units up

Applying the rule of the translation

Step1

A(-2, 2) = A'(-2-2 , 2+8) = A'(-4 , 10)

Step 2

B(−2, 4) = B'(-2-2 , 4+8) = B'(-4, 12)

Step 3

C(2, 4) = C'(2-2 , 4+8) = C'(0, 12)

Step 4

D(2, 2) = D'(2-2 , 2+8) = D'(0, 10)

Describe what characteristics you would find if the corresponding vertices were connected with line segments.

If point A was connected to point A', point B was connected to point B',point C was connected to point C', point D was connected to point D' then all of these line will be parallel to each other, since they were all transformed by the same amount (x-2, y+8).

5 0

3 years ago

L= a+(n-1)d <br><br>SOLVE FOR N

Deffense [45]

Answer:

$n = \frac{l-a}{d}+1$

Step-by-step explanation:

$l= a+(n-1)d\\$

$l -a =(n+1)d$

Divide both sides of the equation by d

$\frac{l-a}{d} = \frac{(n-1)}{d}\\ \\\frac{l-a}{d} = n-1\\\\\frac{l-a}{d}+1 = n$

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4 years ago

PLEASE HELP!!! ............

SVEN [57.7K]

Answer:

No, it is not a function.

Step-by-step explanation:

Vertical line test. A function can only have one output, y, for each unique input, x.

3 0

3 years ago

I need help on question 7 and 8

DanielleElmas [232]

7.
remember
(ab)/(cd)=(a/c)(b/d)
we can split them up
and
(x^m)/(x^n)=x^(m-n)

$\frac{27k^5m^8}{4k^3*9m^2}= \frac{27k^5m^8}{36k^3m^2}=( \frac{27}{36} )( \frac{k^5}{k^3} )( \frac{m^8}{m^2} )$ = $( \frac{3}{4})(k^{5-3})(m^{8-2} )=( \frac{3}{4})(k^2)(m^6 )= \frac{3k^2m^6}{4}$

9.

2 to 3
4(x-1)=15
to
4x-1=15
the distribuutive prperty
a(b-c)=ab-ac
what he did was
a(b-c)=ab-c

he did not distribute the 4 to the -1

4(x-1)+3=18
minus 3
4(x-1)=15
distribute 4 to x and -1
4x-4=15
add 4 to both sides
4x=19
divide by 4
x=19/4

4 0

3 years ago