The hypotenuse of a right triangle is 25 cm, and the shorter leg is 15 cm. Find the length of the other leg.
Answer:
The other leg is 20 cm
So the equation for the Pythagorean theorem is
a^2+b^2=c^2
The hypotenuse is always the c. It does matter if 25 is plugged into a or b. So
15^2=225 and c^2=25^2=625
So subtract 225 from both sides. You have a^2(or b^2)=400. Square root on both sides. There, a^2(or b^2), i.e. the other leg, is 20 cm.
We are comparing maxima. From the graph we know that the max of one graph is +2 at x = -2. What about the other graph? Need to find the vertex to find the max.
Complete the square of <span>h(x) = -x^2 + 4x - 2:
</span>h(x) = -x^2 + 4x - 2 = -(x^2 - 4x) -2
= -(x^2 - 4x + 4 - 4) - 2
=-(x^2 - 4x + 4) -2+4
= -(x-2)^2 + 2 The equation describing this parabola is y=-(x-2)^2 + 2, from which we know that the maximum value is 2, reached when x = 2.
The 2 graphs have the same max, one at x = -2 and one at x = + 2.
I think is might be C but I’m not completely sure so maybe the one ther guys one is right
