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Stella [2.4K]
3 years ago
10

Find the perimeter of a quadrilateral with vertices at C (-1,2), D (-2,-1), E (2,-2), and F (1,1). Round to the nearest hundredt

h when necessary.
A.) 10.92
B.) 12.68
C.) 13.43
D.) 18.27
Mathematics
2 answers:
stealth61 [152]3 years ago
7 0
To answer, find the distance from point C to D, point D to E, point E to F, and point F to C. The formula for the distance is,
                                     d = sqrt ((x2 - x1)² + (y2 - y1)²)
  Point C to D                d1 = sqrt ((-3 - -2)² + (1 - 4)²) = 3.16 units
  Point D to E                d2 = sqrt ((1 - -3)² + (0 - 1)²) = 4.12 units
  Point E to F                 d3 = sqrt ((-1 - 1)² + (2 - 0)²) = 2.83 units
  Point F to C                 d4 = sqrt ((-1 - -2)² + (2 - 4)²) = 2.23 units 
Then, add up all the distances and the answer is 12.34 units. The closest answer is letter D.  Credit:Meerkat
hodyreva [135]3 years ago
4 0

Answer:

do you know what the answer was?? i have this same question and i dont want to get it wrong !!

Step-by-step explanation:

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\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

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so let's start ~

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hope helpful :D

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