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3 years ago

5

the average lifespan of a horse is 40 years, which is five times longer than the average lifespan of a guinea pig. Use the bar d

iagram below to find the average lifespan of a guinea pig. Label each section of the diagram

1 answer:

polet [3.4K]3 years ago

3 0

All you have to do is divide 40 by five and you've got your answer. I don't have the required diagram, but that would basically mean that the average lifespan of a guinea pig is about eight years, which is being generous in reality (they usually live for about 4-8 years in real life).

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ivann1987 [24]

For the top angles you would solve them by setting them equal to each other, so you would do 3x+5=17x-70. You can then add 70 to both sides, getting 3x+75=17x. You can then subtract 3x from both sides, getting 75=14x. You then divide both sides, getting 5 5/14 or around 5.36 as x. You can then add plug that into 3x+5, getting around 21.07. You can then make the equation R=180-21.07. You'd get 158.93.

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3 years ago

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

<u>Find the distance DC</u>

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

<u>Find the area of the triangle</u>

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

4 0

3 years ago

Read 2 more answers

I need help on 2 & 3

lora16 [44]

Answer:

NUMBER TWO IS ------ 22,29,37

I DONT KNOW NUMBER THREE

Step-by-step explanation:

I HOPE I HELPED U 229 999 0523

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3 years ago

A line passes through the points (-4,1) and (-3,3). This line can be modeled by the equation y

skelet666 [1.2K]

Answer:

A

Step-by-step explanation:

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3 years ago

Find all ratios that are equivalent to 4 : 6 and have a first term that is less than 40.

kherson [118]

Answer:

2: 3, 4: 6, 6: 9, 8: 12 , 10: 15, 12: 18, 14: 21, 16: 24, 18: 27, 20: 30, 22: 33, 24:36, 26: 39, 28: 42, 30: 45, 32: 48, 34: 51, 36: 54, 38: 57

Step-by-step explanation:

The ratio 4: 6 can be simplified to 2:3 by dividing by 2 to each side of the ratio. After simplified to 2:3, you add the ration to itself to get the rest of the terms.

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3 years ago