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Orlov [11]
4 years ago
5

If sldg is an isosceles tropezoid what is the value of x

Mathematics
2 answers:
tamaranim1 [39]4 years ago
4 0
13 for apex. good luck!
Sergeeva-Olga [200]4 years ago
3 0
If <span>SD is 8x-5 and LG is 6x+21, then the answer is 13. (APEX)</span>
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A scientist estimated that a mixture would need 5 millimeters of a chemical to balance. The actual amount d was 7 millimeters. W
Travka [436]

Answer:

29%

Step-by-step explanation:

If 7 is 100% correct then 5 would only be a portion of it

So you need to divide 5 by 7

So 5 divided by 7 is .714 or .71

this means the error was 29%

3 0
3 years ago
In triangle RST, m∠R &gt; m∠S + m∠T. Which must be true of triangle RST? Check all that applym∠R &gt; 90°
Sedbober [7]

Answer: The correct statements are,

m∠R > 90°

m∠S + m∠T < 90°

m∠R > m∠T

m∠R > m∠S

Step-by-step explanation:

Here, RST is a triangle,

Therefore,  m∠R+m∠S+m∠T = 180° ⇒ m∠S+m∠T = 180° - m∠R

Given: m∠R > m∠S + m∠T

⇒ - m∠R < - (m∠S + m∠T) (by multiplying-1 on both sides)

⇒ 180°- m∠R < 180° - (m∠S + m∠T) (by adding 180° on both sides)

⇒ m∠S+m∠T < 180° - (m∠S + m∠T)

⇒ m∠S+m∠T+ m∠S+m∠T < 180° ( by adding m∠S + m∠T on both sides)

⇒ 2(m∠S+m∠T) < 180°

⇒ m∠S+m∠T < 90°

⇒ m∠R > 90° ( because m∠R+m∠S+m∠T = 180° )

Again, m∠R > m∠S + m∠T

⇒ m∠R > m∠S and  m∠R > m∠T

Thus, Option first second fourth and fifth are correct.


Note: m∠S = m∠T is only possible when m∠R=90° (but it is not given)

That is why m∠S = m∠T is not correct.

And, there are not enough information to prove m∠S > m∠T

That is why  m∠S > m∠T is also incorrect.

3 0
3 years ago
Read 2 more answers
X^2 + 5x = quadratic equation <br>=​
timama [110]

Hi there!

The question gives us the quadratic equation , and it tells us to solve it using the quadratic formula, which goes as . However, we must first find the values of a, b, and c. The official quadratic equation goes as , which matches the format of the given quadratic equation. Hence, the value of a would be 1, the value of b would be 5, and the value of c would be 3. Now, just plug it back into the quadratic equation and simplify to get the zeros of the equation. 

x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a}  

x = \frac{-(5) \pm \sqrt{(5)^2 - 4(1)(3)} }{2(1)}  

x = \frac{-5 \pm \sqrt{25 - 12} }{2}  

x = \frac{-5 \pm \sqrt{13} }{2}  

x = \frac{-5 \pm 3.61 }{2}  

x = \frac{-5 + 3.61 }{2}, x = \frac{-5 - 3.61 }{2}

x=-0.695 \ \textgreater \ \ \textgreater \  -0.7, x= -4.305 \ \textgreater \ \ \textgreater \ x=-4.31

Therefore, the solutions to the quadratic equation  are x = -0.7 and x = -4.31. Hope this helped and have a phenomenal day!

Your answer is 4.31

4 0
3 years ago
5(x+12)=95 solve for x
____ [38]
Use Photomath it's free :)
6 0
3 years ago
Read 2 more answers
I kneed help
bonufazy [111]

Answer:

thats pretty easy its A

Step-by-step explanation:

cuz its talking about candidates

6 0
3 years ago
Read 2 more answers
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