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k0ka [10]
3 years ago
13

24.50 divided by 6 PLZ HELP! I DON'T HAVE MUCH TIME!

Mathematics
1 answer:
Alex17521 [72]3 years ago
6 0

Answer:

the answer is 4.833333


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What is the answer to this question i have a screen shot
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Answer:

Put the screenshot on the question

Step-by-step explanation:

I can't answer it without a screenshot

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A figure was translated 5 units down and 6 to the left and then reflected over the line
aivan3 [116]

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C

Step-by-step explanation:

only a dilation would make the figures not congruent/similar

8 0
3 years ago
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Select the properties that equilateral triangles and isosceles triangles have in common.
defon

The properties that equilateral triangles and isosceles triangles have in common is that they have two equal sides.

<h3>What is a triangle?</h3>

A triangle is a polygon that has three sides and three angles. Types of triangles are<em> isosceles, equilateral </em>and<em> scalene</em> triangle.

An equilateral triangle is a triangle that have three equal sides while isosceles triangle have two equal sides.

The properties that equilateral triangles and isosceles triangles have in common is that they have two equal sides.

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7 0
2 years ago
HELP QUICK WILL GIVE BRAINLIEST
agasfer [191]
Can’t see what’s that
4 0
3 years ago
Read 2 more answers
A metal hollow bar whose cross section and dimension are shown below weighs 8x10^3 kg/m^3 and measure 2m in length ..determine t
devlian [24]
1) We calculate the volume of a metal bar (without the hole).

volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²

Volume=(0.935 m²)(2 m)=1.871 m³

2) we calculate the volume of the parallelepiped

Volume of a parallelepiped= area of the section  x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³

3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar -  volume of a parallelepiped

Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³

4) we calculate the mass of the metal bar

density=mass/ volume  ⇒ mass=density *volume

Data:
density=8.10³ kg/m³
volume=1.551 m³

mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg

answer: The mas of the metal bar is 12.408x10³ kg  or   12408 kg  


4 0
3 years ago
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