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2 years ago

How to factor x^2+8x+12

Mathematics

2 answers:

Setler [38]2 years ago

5 0

x^2+8x+12 = (x + 6)(x + 2)

Sonbull [250]2 years ago

3 0

X^2+8x+12
(x )(x ) We know x has to appear twice
Then we say what two numbers multiplied together gets you 12 and when added together gets you 8
We know thats 2 and 6
(x 2)(x 6)
And since they are both positive...
(x+2)(x+6)

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Answer:C.

Step-by-step explanation:

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2 years ago

How do you do this. Please give a full answer and explain why.

OverLord2011 [107]

Law of Exponent

$\displaystyle \large{ {a}^{ - n} = \frac{1}{ {a}^{n} } }$

Compare the terms.

$\displaystyle \large{ {a}^{ - n} = {( - 2)}^{ - 3} }$

Therefore, a = -2 and n = 3. From the law of exponent above, we receive:

$\displaystyle \large{ {( - 2)}^{ - 3} = \frac{1}{ {( - 2)}^{ 3} } }$

Exponent Def. (For cubic)

$\displaystyle \large{ {a}^{3} = a \times a \times a }$

Factor (-2)^3 out.

$\displaystyle \large{ {( - 2)}^{ - 3} = \frac{1}{( - 2) \times ( - 2) \times ( - 2)}}$

(-2) • (-2) = 4 | Negative × Negative = Positive.

$\displaystyle \large{ {( - 2)}^{ - 3} = \frac{1}{4 \times ( - 2)}}$

4 • (-2) = -8 | Negative Multiply Positive = Negative.

$\displaystyle \large{ {( - 2)}^{ - 3} = \frac{1}{ - 8}}$

If either denominator or numerator is in negative, it is the best to write in the middle or between numerator and denominators.

Hence,

$\displaystyle \large \boxed{ {( - 2)}^{ - 3} = - \frac{1}{ 8}}$

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2 years ago

I was wondering what the answer to these problems is?

alina1380 [7]

The first one is 4
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Solve System Below 5x + 8y = 3 5x + 9y = 3

Aleks04 [339]

Answer:

Step-by-step explanation:

-5x - 8y = -3

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y = 0

5x + 0 = 3

5x = 3

x = 3/5

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