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kupik [55]
3 years ago
10

How to find the area of parallelograms a=bh

Mathematics
1 answer:
saw5 [17]3 years ago
8 0
To find the area if a parallelogram you multiply the base with the height ti get the area. base x height= area
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MEDAAAL :D
Sonja [21]
<span>The answer is 2431.01. At the end of the first year, 5 percent of 2000 is taken and added on to the 2000 you started with. At the end of the second, another 5 percent of that higher number is taken and added on, and so on and so forth until you end up receiving 2431.01 in total after 4 years.</span>
8 0
3 years ago
Zareena has 24 minutes to work on her math homework and each problem is taking g her 2/3 of a minute on average to complete whic
adelina 88 [10]

Answer:

16

Step-by-step explanation:

if it takes her 2/3 a minute then

24 divided by 2/3 is the answer

3 0
3 years ago
marathon runner runs26.2 miles at the pace of 6.2 minute per mile round off answer to the nearest minute how long will it take t
Scorpion4ik [409]
There are several methods of rounding, but in this case the 'best' one is probably to round up. Rounding down suggests that Kathy actually ran faster. 

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3 0
3 years ago
What is the value of -9r - 7 when r = 2?<br> -25<br> -18<br> 11<br> 45
AlexFokin [52]
Substitute the variable for value we're given.

-9(2) - 7
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So, -25 is the answer.
5 0
3 years ago
Read 2 more answers
Find the volume V obtained by rotating the region bounded by the curves about the given axis.
BartSMP [9]

Using the disk method, the volume is given by the integral

\displaystyle \pi \int_{\pi/2}^\pi (9\sin(x))^2\,\mathrm dx = 81\pi \int_{\pi/2}^\pi \sin^2(x)\,\mathrm dx

That is, each disk has a radius of <em>y</em> = 9 sin(<em>x</em>) and hence area = <em>π</em> (9 sin(<em>x</em>))². Add up infinitely many such disks by integrating. Then the volume is

\displaystyle 81\pi \int_{\pi/2}^\pi \sin^2(x)\,\mathrm dx = \frac{81\pi}2 \int_{\pi/2}^\pi (1-\cos(2x))\,\mathrm dx \\\\ =\frac{81\pi}2 \left(x-\frac{\sin(2x)}2\right)\bigg|_{\pi/2}^\pi \\\\ = \frac{81\pi}2 \left( \left(\pi-\frac{\sin(2\pi)}2\right) - \left(\frac\pi2 - \frac{\sin(\pi)}2\right) \right) \\\\ = \boxed{\frac{81\pi^2}4}

8 0
3 years ago
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