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4 years ago

What is 2 1/2 divided by (-1 3/4) as a mixed number? simplest form please

2 answers:

8 0

Start by changing both into improper fractions.
Multiply the denominator and whole number, the add the numerator.
2 x 2 + 1= 5
2 1/2= 5/2
1 x 4 + 3= 7
-1 3/4= -7/4

Now do 5/2 multiplied by the reciprocal of -7/4 which is -4/7.
5/2 x -4/7= -20/14
Simplify to -10/7 by dividing by 2
Change it to a mixed number
Answer is -1 3/7

Nezavi [6.7K]4 years ago

5 0

Your answer is - 1 and 3/7

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3 years ago

What is the value of C?<br>14 = -2C - 6 – 3C <br>

icang [17]

Answer:

C = -4

Step-by-step explanation:

First, combine like terms (terms with the same amount of variables):

14 = -2C - 3C - 6

14 = (-2C - 3C) - 6

14 = (-5C) - 6

Isolate the variable, C. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. PEMDAS is the order of operation, and equals:

Parenthesis

Exponents & Roots

Multiplication

Division

Addition

Subtraction.

First, add 6 to both sides:

14 (+6) = -5C - 6 (+6)

14 + 6 = -5C

-5C = 20

Next, divide -5 from both sides:

(-5C)/-5 = (20)/-5

C = 20/-5

C = -4

-4 is your value for C.

7 0

3 years ago

Read 2 more answers

A group of retailers will buy 104 televisions from a wholesaler if the price is $300 and 144 if the price is $250. The wholesale

const2013 [10]

Answer:

(275,122)

When the price will be $275, the quantity will be 122 televisions.

Step-by-step explanation:

We have been given that a group of retailers will buy 104 televisions from a wholesaler if the price is $300 and 144 if the price is $250.

As the quantity of televisions depends on price of televisions, so our demand curve will pass through points (300,104) and (250,144).

Let us find slope of demand line using slope formula.

$m=\frac{y_2-y_1}{x_2-x_1}$ , where,

$m =\text{Slope of line}$ ,

$y_2-y_1=\text{Difference between two y-coordinates}$ ,

$x_2-x_1=\text{Difference between same x-coordinates of two y-coordinates}$

Upon substituting coordinates of our given points in slope formula we will get,

$m=\frac{104-144}{300-250}$

$m=\frac{-40}{50}$

$m=-\frac{4}{5}$

Let us substitute $m=-\frac{4}{5}$ coordinates of point (250,144) in slope intercept form of equation ( $y=mx+b$ ).

$144=-\frac{4}{5}*250+b$

$144=-4*50+b$

$144=-200+b$

$144+200=-200+200+b$

$344=b$

Upon substituting $b=344$ and $m=-\frac{4}{5}$ we will get equation of our demand line as:

$y=-\frac{4}{5}x+344$

Similarly we will find the equation of supply line using points (225,88) and (315,168).

$m=\frac{168-88}{315-225}$

$m=\frac{80}{90}$

$m=\frac{8}{9}$

Let us substitute $m=\frac{8}{9}$ and coordinates of point (225,88) in slope intercept form of equation ( $y=mx+b$ ).

$88=\frac{8}{9}*225+b$

$88=8*25+b$

$88=200+b$

$88-200=200-200+b$

$-112=b$

Upon substituting $b=-112$ and $m=\frac{8}{9}$ we will get equation of our supply line as:

$y=\frac{8}{9}x-122$

Let us equate both lines to find the point where both lines intersect.

$-\frac{4}{5}x+344=\frac{8}{9}x-122$

$-\frac{4}{5}x-\frac{8}{9}x+344=\frac{8}{9}x-\frac{8}{9}x-122$

$-\frac{4}{5}x-\frac{8}{9}x+344=-122$

$-\frac{4}{5}x-\frac{8}{9}x+344-344=-122-344$

$-\frac{4}{5}x-\frac{8}{9}x=-466$

Let us have a common denominator.

$-\frac{4*9}{5*9}x-\frac{8*5}{9*5}x=-466$

$-\frac{36}{45}x-\frac{40}{45}x=-466$

$\frac{-36-40}{45}x=-466$

$\frac{-76}{45}x=-466$

$\frac{-76}{45}*\frac{45}{-76}x=-466*\frac{45}{-76}$

$x=466*\frac{45}{76}$

$x=6.1315789473684211*45$

$x=275.9210526315789495\approx 275$

Let us substitute x=275 in any of our equation to solve for y.

$y=-\frac{4}{5}*275+344$

$y=-4*55+344$

$y=-220+344$

$y=122$

Therefore, the equilibrium point for the market will be (275,122).

5 0

3 years ago