Answer:
He paid = $20,500
Step-by-step explanation:
Let the amount he bought the car originally be X
so from the statement,
(2/5)*X + $200 = $8,400
(2/5)*X = $8,400 - $200
solving for X
X = $8200 * 5/2
X = $20,500
Answer:
$99.34
Step-by-step explanation:
Answer:
Option B is correct.
Weight of a bowling ball is 5.24 Ib
Step-by-step explanation:
Assume: The shape of the bowling ball is perfectly spherical.
Given:
Radius of a bowling ball= 5 inches (r) .
One cubic inch weighs
th of a pound.
Density of a bowling ball = ![\frac{1}{100} Ibs/in^3](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B100%7D%20Ibs%2Fin%5E3)
Volume of sphere is given by:
where V is the volume and r is the radius of the sphere.
Substitute the value of r =5 and
in above we get;
![V = \frac{4}{3} \cdot 3.14 \cdot 5^3 =\frac{4}{3} \cdot 3.14 \cdot 125](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%7D%7B3%7D%20%5Ccdot%203.14%20%5Ccdot%205%5E3%20%3D%5Cfrac%7B4%7D%7B3%7D%20%5Ccdot%203.14%20%5Ccdot%20125)
Simplify:
![V = 523.3333... in^3](https://tex.z-dn.net/?f=V%20%3D%20523.3333...%20in%5E3)
To find the weight of a bowling ball:
![Weight = Volume \times Density](https://tex.z-dn.net/?f=Weight%20%3D%20Volume%20%5Ctimes%20Density)
Then;
![Weight = 523.33333.. \times \frac{1}{100} =\frac{523.3333..}{100} = 5.2333...](https://tex.z-dn.net/?f=Weight%20%3D%20523.33333..%20%5Ctimes%20%5Cfrac%7B1%7D%7B100%7D%20%3D%5Cfrac%7B523.3333..%7D%7B100%7D%20%3D%205.2333...)
Therefore, the weight of a bowling ball ≈ 5.24 Ib