The diagonal of a rhombus divides it into two congruent isosceles triangles.
So ∠CBD ≅ ∠CDB
∠CBD + ∠CDB + 68 = 180
2∠CBD = 180 - 68 = 112
∠CBD = 56
We also have
∠BDE + ∠E + ∠DBE = 180
∠DBE = 180 - 73 - 36 = 71
∠EBC = ∠EBD - ∠CBD = 71 - 56 = 15
Answer: ∠EBC = 15 degrees
Answer:
$15
Step-by-step explanation:
To figure thsi out, you do 20 divided by 8, which gives you 2.5 ($2.50.)
Next you do 2.50 x 6 which gives you 15 ($15.)
The answer is $15.
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The volume of the cylinder is; 128π in3
Base area(πr^2)*height
Π = 3.14
Therefore; 3.14 * 4^2 * 8
3.14 * 128
= 401.92 in3
(6 + 5i)(4 + 7i) = 24 + 42i + 20i + 35i²
= 35i² + 62i + 24
The product of 6+5i and 4+7i is 35i² + 62i + 24.
Answer:
When c and a are positive or both are negative
Step-by-step explanation:
negative times negative equals positive so if a was negative and c was negative -a*-c= ac
Of course positive times positive equals negative so if a and c were positive we could do
a*c= ac
Hope I could help !
