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3 years ago

I really need help with these problems

Mathematics

1 answer:

White raven [17]3 years ago

4 0

10.
$x^2+14x+48=x^2+6x+8x+48=x(x+6)+8(x+6)=\boxed{(x+6)(x+8)}$

11.
$\dfrac{t^2-4t-32}{t-8}=\dfrac{t^2-8t+4t-32}{t-8}=\dfrac{t(t-8)+4(t-8)}{t-8}\\\\=\dfrac{(t-8)(t+4)}{t-8}=t+4\\\\Answer:\boxed{t+4;\ t\neq8}$

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BRAINLIEST ASAP! PLEASE HELP ME :)

Firdavs [7]

Answer:

1.) 120? (Same angle just flipped around.)

2.) -2 (you flip the stuff: (3,2)(4,6) = (3,4) (2,6)

it's x1,y1, x2, y2 for number 2.. That's the formula.

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3 years ago

A and B are two similar ornaments in the shape of a fish. The surface area of 44.8 cm and the surface area of B 179.2 cm Find th

ASHA 777 [7]

Answer:

400 cm

Step-by-step explanation:

1 cm = 1000m

44.8 cm=?

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2 years ago

The formula for the circumference of a circle is c= 2pi r, where r is the radius. Rearrange the formula to solve for our and sel

ratelena [41]

Answer: r = C/(2pi)

This is the same as writing $r = \frac{C}{2\pi}$

=========================================================

Explanation:

pi is some number (approximately 3.14) which means 2pi is also some number (roughly 6.28)

Saying c = 2pi*r means we have 2pi times r, and the result is the circumference c. To isolate r, we'll undo the multiplication. We'll undo it by dividing both sides by 2pi like so

C = 2pi*r

C/(2pi) = r

r = C/(2pi)

in which we can write it like $r = \frac{C}{2\pi}$

So whatever C is, we divide it over 2pi (aka roughly 6.28) to get the radius.

-----------------

Extra Info (Optional Section):

As an example, let's say the circumference of the circle is 628 feet. This means the distance around the circle is 628 feet. So C = 628 would lead to...

r = C/(2pi)

r = C/(6.28)

r = 628/(6.28)

r = 100

So the radius would be roughly 100 feet.

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3 years ago

Car insurance of 800 Is twice what it was a decade ago. Find the cost of the insurance then

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Answer:

it was 400 back then, a decade ago

Step-by-step explanation:

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3 years ago

Neptune's average distance from the sun is 4.503 × 109 km. mercury's average distance from the sun is 5.791 × 107 km. about how

vladimir1956 [14]

Neptune's distance from the sun is d₁ = 4.503 x 10⁹ km.
Mercury's distance from the sun is d₂ = 5.791 x 10⁷ km.

Calculate the number of times d₁ is greater than d₂.
$\frac{d_{1}}{d_{2}} = \frac{4.503 \times 10^{9}}{5.791 \times 10^{7}} = 77.75859$

Answer: 7.7759 x 10⁻¹ times

4 0

3 years ago