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3 years ago

What is algebra in 5th grade

Mathematics

2 answers:

katrin [286]3 years ago

6 0

Fifth grade algebra and functions worksheets contain math problems with variables.

slamgirl [31]3 years ago

5 0

Types of angles , perimeters, area , shapes , circumference , pythagorean theorem if you are asking those kinds of questions those are all involved in 5th grade algebra

You might be interested in

Which term describes the set of all possible output values for a function?

Firdavs [7]

The correct answer is:

C. Range

Explanation:

The definition of domain is the set of all possible input values, or x-values, of a function.

The definition of range is the set of all possible output values, or y-values, of a function.

3 0

3 years ago

Read 2 more answers

Sandra wants to purchase necklaces that cost $4.99. She already purchased 3 bracelets for $8.97. Which of the following function

Volgvan

The answer is A

Y= 4.99x + 8.97

6 0

2 years ago

If line L is perpendicular to line m and the slope of line L is undefined, what is the slope of line m?

Delicious77 [7]

Step-by-step explanation:

mL = Undefined

mM = ?

mL × mM = -1

mM = -1 ÷ mL

mM = -1/mL

mM = -1/Undefined

mM = -1/(1/0)

mM = (-1 × 0)/1

mM = 0

Slope of line m is 0

Option → C

8 0

2 years ago

Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va

Burka [1]

Answer:

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

The polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

$\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)$

with

$\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}$

for some c in the interval (-x, x)

In the particular case f

f(x)=cos(x)

we have

$\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)$

therefore

$\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0$

and the polynomial approximation of T5(x) of cos(x) would be

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

$\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}$

for some c in (-x,x). So

$\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}$

and we must find the values of x for which

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652$

Working this inequality out, we find

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815$

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0

2 years ago

What is the value of the y-coordinate for point S?

natka813 [3]

The answer is for the value of y-coordinate is -5

5 0

2 years ago

Read 2 more answers