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3 years ago

Please Help !!! I attached the problem below :) I'm awarding 20 points and a trophy so please answer quickly

Mathematics

1 answer:

never [62]3 years ago

6 0

I believe your answer is a,b,b

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How do you use multiplication and the distributive property to find 144÷8

yuradex [85]

You can do 144 times 1/8, which is the same thing as 144÷8.
The answer is 18.

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3 years ago

Simplify. Express your answer as a single term using exponents. 960*5x960*9

adelina 88 [10]

${960}^{5} \times {960}^{9} \\ = {960}^{5 + 9} \\ = {960}^{14}$

Answer:

${960}^{14}$

Hope you could get an idea from here.

Doubt clarification - use comment section.

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2 years ago

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3 years ago

Please helppp with this math question <333

Naya [18.7K]

Answer:

The average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

Step-by-step explanation:

We are given the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$

We need to find average rate of change.

The formula used to find average rate of change is : $Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}$

We have b=-1 and a=-11

Finding g(b) = g(-1)

$g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9$

Finding g(a) = g(-11)

$g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29$

Finding average rate of change

$Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1$

So, the average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

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3 years ago

SOMEONE PLEASE HELP MEEEE

AURORKA [14]

Answer:

$-180^{\circ}$

Step-by-step explanation:

Lines form 180 degrees on either side. The negative sign simply implies direction (clockwise instead of counter-clockwise), which is negligible as 180 is exactly half of 360 so you'd form the same line.

8 0

3 years ago

Read 2 more answers