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Ira Lisetskai [31]
3 years ago
9

Brian and his son have a total age of 84.Brian is 26 years older than his son .how old is Brian? ​

Mathematics
2 answers:
Dimas [21]3 years ago
7 0
Brian and his son are 42. 84/2=42
nevsk [136]3 years ago
5 0

Answer:

Brian = 55

Son = 29

Step-by-step explanation:

Let the ages of Brian and his son be

x +26 and x

Given that :

x + x + 26 = 84

2x + 26 = 84

2x = 58

x = 29.

We know that x is the age of Brian's son. so, Brian's age is 29 + 26 = 55

Hope this helps.

Good Luck

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A professor knows that her statistics students' final exam scores have a mean of 79 and a standard deviation of 11.3. In his cla
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For each student, there are only two possible outcomes. Either they score an A, or they do not. The probability of a student scoring an A is independent of any other student, which means that the binomial probability distribution is used to solve this question.

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And p is the probability of X happening.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean and standard deviation , the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Proportion of students that scored an A:

Scores have a mean of 79 and a standard deviation of 11.3, which means that \mu = 79, \sigma = 11.3

Scores of 90 or higher are graded an A, which means that the proportion is 1 subtracted by the p-value of Z when X = 90, so:

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 79}{11.3}

Z = 0.97

Z = 0.97 has a p-value of 0.8340.

1 - 0.8340 = 0.166

The proportion of students that scored an A is 0.166.

Probability that 6 students or more will score an "A" on the final exam:

Binomial distribution.

22 students, which means that n = 22

The proportion of students that scored an A is 0.166, which means that p = 0.166

The probability is:

P(X \geq 6) = 1 - P(X < 6)

In which

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{22,0}.(0.166)^{0}.(0.834)^{22} = 0.0184

P(X = 1) = C_{22,1}.(0.166)^{1}.(0.834)^{21} = 0.0807

P(X = 2) = C_{22,2}.(0.166)^{2}.(0.834)^{20} = 0.1687

P(X = 3) = C_{22,3}.(0.166)^{3}.(0.834)^{19} = 0.2239

P(X = 4) = C_{22,4}.(0.166)^{4}.(0.834)^{18} = 0.2117

P(X = 5) = C_{22,5}.(0.166)^{5}.(0.834)^{17} = 0.1517

Then

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0184 + 0.0807 + 0.1687 + 0.2239 + 0.2117 + 0.1517 = 0.8551

P(X \geq 6) = 1 - P(X < 6) = 1 - 0.8551 = 0.1449

Thus

0.1449 = 14.49% probability that 6 students or more will score an "A" on the final exam.

For a problem that used the normal distribution, you can check brainly.com/question/15181104, and for a problem that used the binomial distribution, you can check brainly.com/question/15557838

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