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1 answer:
ΔAOB is a right angled triangle. Therefore the Pythagorean Theorem applies in this situation. θ is the angle from a standard position of the line OA The length of the y component is √(1-0)2 +(-3-(-3))2] =√(12+ 02) = 1 A(-3,1) to B(-3,0) which is opposite Then the length of the x-component is √[(-3-0)2 +(0-0)2] = √(9+0)= 3 B(-3,0) to O(0,0) which is adjacent The length of vector OA is √[(-3-0)2 + (1-0)2] = √(9+1) = √(10) A(-3,1) to O(0,0) which is the hypotenuse of the triangle θ = 180 - α sinθ = sin(180-α) = opposite/hypotenuse = 1/√10 cosθ = adjacent/hypotenuse = -3/√10 tanθ = opposite/adjacent = 1/-3 = -1/3 α= arcsin(1/√10) ≈ 18 θ =180 -18 ≈162
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Step-by-step explanation:
Answer:
144-36=108
Square root 108 = 10.4cm (cb)
Soh Cah toa
Sin(55) =o/h
=10.4/h
xh
H x sin55 =10.4
÷sin55
H= 10.4/sin55
H=12.7cm
CD is 12.7cm to 3 s . f .
Answer: 110 Solution: 12% of 125= 15 125-15= 110 Hope you get it.