Answer:
Kite
Step-by-step explanation:
To graph quadrilateral with points:
A(-1,-2)
B(5,1)
C(-3,1)
D(-1,4)
Thus, we graph the the given points and join the corners. The quadrilateral formed has the following features:
Measure of segment AB= Measure of segment BD = 6.708 units
Measure of segment AC= Measure of segment CD = 3.605 units
Thus, adjacent pair of sides of the quadrilateral are congruent.
Major diagonal BC cuts the minor diagonal AD at point E such that:
Measure of segment AE= Measure of segment ED = 3 units
m∠AEB = m∠DEB = 90°
Thus, major diagonal is a perpendicular bisector of the minor diagonal.
The above stated features fulfills the criterion of a kite.
Hence, the given quadrilateral ABCD is a kite.
Answer:
37 dimes and 10 nickels
Step-by-step explanation:
let d = # dimes
let n = # nickels
we can set up a system of equations:
n + d = 47
.05n + .10d = 4.2
if we solve the first equation for 'n' we get:
n = 47-d
now we can substitute this in for 'n' in the second equation:
.05(47-d) + .10d = 4.2
2.35 - .05d + .10d = 4.2
2.35 + .05d = 4.2
subtract 2.35 from each side to get:
.05d = 1.85
d = 1.85÷.05
d = 37
if d+n = 47 and d=37 then n = 10
Check:
.05(10) + .1(37) should equal 4.2
.50 + 3.7 = 4.2 [It Checks Out]
Answer:
Answer: GCF of 4 and 10 is 2.
Step-by-step explanation:
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Answer:
The p value for this case would be given by:
Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.
Step-by-step explanation:
Information provided
represent the sample mean
represent the population deviation
sample size
represent the value that we want to test
represent the significance level
z would represent the statistic
represent the p value
Hypothesis to test
We want to test if the true mean is at least 20 ounces, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
The statistic is given by:
(1)
Replacing the info given we got:
The p value for this case would be given by:
Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.
