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Licemer1 [7]
3 years ago
14

Express this number in scientific notation. 763 thousandths

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
6 0
Hello there! 763 thousandths in standard form is 0.763. When it comes to scientific notation, the number being multiplied by a power of 10 has to be greater than or equal to 1, but less than 10. In this case, the number is 7.63. To get this number, you would have to move the decimal to the left 1 time. When you on a calculator, 7.63 * 0.1 is 0.763. 763 thousandths in scientific notation is 7.63 * 10^-1.
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See the attached diagram, it has all the information you need.

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3 years ago
(problem 6.13 page 97) Consider a population in which 80% of males and 60% of females are employed. In this population, 55% of i
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Answer:

There is a 50.77% probability that no more than one of those chosen is not employed.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they will be employed, or they will not. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

We have these following percentages:

55% of the individuals are female.

So 45% of the individuals are male.

80% of males are employed. So 20% of males are unemployed.

60% of females are employed. So 40% of females are unemployed.

If I pick five persons at random from this population, what is the probability that no more than one of those chosen is not employed?

Using the binomial distribution, p is the probability that a person is unemployed. 40% of the females and 20% of the males are unemployed. The population is 55% females and 45% males. So

p = 0.4*0.55 + 0.2*0.45 = 0.31

There are five persons, so n = 5

What is the probability that no more than one of those chosen is not employed?

P(X \leq 1) = P(X = 0) + P(X = 1)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.31)^{0}.(0.69)^{5} = 0.1564

P(X = 1) = C_{5,1}.(0.31)^{1}.(0.69)^{4} = 0.3513

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.1564 + 0.3513 = 0.5077

There is a 50.77% probability that no more than one of those chosen is not employed.

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