What is the pereimeter of (14x8)(14x8)

The length of a school bus is 12.6 meters. If 9 school buses park end to end with 2 meters between each one, what's the total le

weqwewe [10]

Answer:

129.4

Step-by-step explanation:

Calculation for what's the total length from the front of the first bus to the end of the last

First step is to multiply the given number of buses by the length of each one

Hence,

12.6 meters x 9 = 113.4 meters

Second step

Since there are 8 spaces in between we would multiply the 8 spaces by 2 meters

8 x 2 meters = 16

Now let calculate total length from the front of the first bus to the end of the last

16 + 113.4 meters =129.4

Therefore total length from the front of the first bus to the end of the last will be 129.4

7 0

3 years ago

Please help. I will give brainliest!

Andrej [43]

Answer:

Step-by-step explanation:

How to Find Outliers Using the Interquartile Range(IQR)

Step 1: Find the IQR, Q1(25th percentile) and Q3(75th percentile). ...

Step 2: Multiply the IQR you found in Step 1 by 1.5: ...

Step 3: Add the amount you found in Step 2 to Q3 from Step 1: ...

Step 3: Subtract the amount you found in Step 2 from Q1 from Step 1:

7 0

3 years ago

It is impossible to get 6 jacks when selecting cards from a shuffled deck. Express the indicated degree of likelihood as a proba

Vinil7 [7]

Answer:

Probability = 0

Step-by-step explanation:

If something happening is impossible, it's probability of occurring is also 0.

A deck of cards only contains 4 jacks.

Thus you can never get 6 jacks out of the deck without replacing the selected card each time.

Since we are not replacing the cards once we pick them, this event is impossible to occur.

4 0

3 years ago

A is an m×n matrix.Check the true statements below:A. The kernel of a linear transformation is a vector space.B. If the equation

Bess [88]

Answer:

Results are (1) True. (2) False. (3) False. (4) True. (5) True. (6) True.

Step-by-step explanation:

Given A is an $m\times n$ matrix. Let $T :U\to V$ be the corresponding linear transformationover the field F and $\theta$ be identity vector in V. Now if $x\in Ker( T)\implies T(x)=\theta$ .

(1) The kernel of a linear transformation is a vector space : True.

Let $x,y\in Ker( T)$ , then,

$T(x+y)=T(x)+T(y)=\theta+\theta=\theta\impies x+y\in Ker( T)$

hence the kernel is closed under addition.

Let $\lambda\in F, x\in Ker( T)$ , then

$T(\lambda x)=\lambda T(x)=\lambda\times \theta=\theta$

$\lambda x\in Ker(T)$ and thus Ket(T) is closed under multiplication

Finally, fore all vectors $u\in U$ ,

$T(\theta)=T(\theta+(-\theta))=T(\theta)+T(-\theta)=T(\theta)-T(\theta)=\theta$

$\implies \theta\in Ker(T)$

Thus Ker(T) is a subspace.

(2) If the equation Ax=b is consistent, then Col(A) is $\mathbb R^m$ : False

if the equation Ax=b is consistent, then Col(A) must be consistent for all b.

(3) The null space of an mxn matrix is in $\mathbb R^m$

: False

The null space that is dimension of solution space of an m x n matrix is always in $\mathbb R^n$ .

(4) The column space of A is the range of the mapping $x\to Ax$

: True.

(5) Col(A) is the set of all vectors that can be written as Ax for some x. : True.

Here Ax will give a linear combination of column of A as a weights of x.

(6) The null space of A is the solution set of the equation Ax=0.

: True

5 0

3 years ago

The Scott family is trying to save as much money as possible. One way to cut back on the money they spend is by finding deals wh

avanturin [10]

Answer:

Unit price of strawberries at Grocery Mart is $ 1.495 or 150 pennies

Unit price of strawberries at Baldwin Hills Market is $ 1.33 or 133 pennies.

Step-by-step explanation:

1 dollar = 100 pennies

Given:

Cost of 2 pounds of strawberries at Grocery Mart = $ 2.99

Cost of 3 pounds of strawberries at Baldwin Hills Market = $3.99

∵ Cost of 2 pounds of strawberries at Grocery Mart = $ 2.99

∴ Cost of 1 pound of strawberries at Grocery Mart = $\frac{2.99}{2}=\$1.495=1.495\times 100\approx 150\textrm{ pennies}$

∵ Cost of 3 pounds of strawberries at Baldwin Hills Market = $3.99

Cost of 1 pound of strawberries at Baldwin Hills Market = $\frac{3.99}{3}=\$1.33= 1.33\times 100 = 133\textrm{ pennies}$

Therefore, the unit price of strawberries at each grocery store is the cost of 1 pound of strawberries. So, unit rate at Grocery Mart is 150 pennies and at Baldwin Hills Market is 133 pennies.

7 0

3 years ago