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jok3333 [9.3K]
3 years ago
11

Please help with this

Mathematics
1 answer:
AveGali [126]3 years ago
6 0

Answer:

x is 67

Step-by-step explanation:

angles on a straight line.

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Write the phrase as a numerical expression; the product of 5 and 7
steposvetlana [31]

Answer: 12 = 7 + 5

Step-by-step explanation:

12 = 7 + 5

8 0
2 years ago
Sequence: 1,5,13,25<br><br> Find nth term (Equation/formula thingy)<br><br> Need answer ASAP
masha68 [24]

Answer:

Formula for a linear sequence is

Tn=a+(n-1)d

where Tn is the nth term

a is the first term

n is the number of term

d is common difference

4 0
1 year ago
8=1/3(a+5)<br> What does a equal?
IrinaK [193]

Answer: a=19

Step-by-step explanation: In order to solve this question, we must first take out the parenthesis, we can do this by taking 1/3 and multiply it by a and 5. This will give us 8=1/3a+5/3, with this we can subtract 5/3 on both sides of the equation, which will then give us, 19/3=1/3a. Last, we can divide 19/3 by 1/3 giving us 19 as our final anwser. a=19

6 0
3 years ago
Read 2 more answers
100 POINTSSS! ASAP ANSWEERR PLS
Margarita [4]

PART A

Given:

f(x) = 0.69(1.03)x

To find:

If the price of the product is increasing or decreasing and by what percentage

Steps:

we know the formula to find the price of Product A per year, so

f(1) = 0.69 * 1.03 * 1

Price = $0.7107

f(2) = 0.69 * 1.03 * 2

Price = $1.4214

Here the Price of Product after 2 years is greater than the price of Product after one year. So the price of the product A is increasing.

Now to find percentage increase,

Percentage increase = \frac{FV-SV}{SV}*100        (FV = final value, SV = starting value)

Percentage increase = \frac{1.4214 - 0.7107}{0.7107}*100

Percentage increase = \frac{0.7107}{0.7107}*100

Percentage increase = 100 %

Therefore, the percentage increase of Product A is 100%

PART B

Given:

Price of product B in 1st year = $10,100

Price of product B in 2nd year = $10,201

Price of product B in 3rd year = $10,303.01

Price of product B in 4th year = $10,406.04

To find:

Which product recorded a greater percentage change over the previous year

Steps:

We need to find the percentage change of Product B and Product A of each year. We know that the percentage change of product A is 100 % for each year, so we only need to calculate for product B

PC of product B from 1st to 2nd year = \frac{10,201-10,100}{10,100}*100

                                                             = \frac{101}{10,100}*100

                                                             = 0.01 * 100

                                                             = 1 %

PC of product B from 2nd to 3rd year = \frac{10,303.01-10,201}{10,201} *100

                                                              = 1%

PC of product B from 3rd to 4th year =\frac{10,406.04-10,303.01}{10,303.01}*100

                                                              ≈ 1%

So, percentage change of product B is 1% per year

Therefore, Product A has greater percentage change

Happy to help :)

If u need more help, feel free to ask

6 0
3 years ago
Yall I got no brain cells left can you answer this?
MakcuM [25]

Answer:

$6 a week.

Step-by-step explanation:

subtract from week 4-12 and you get $6 a week.

8 0
2 years ago
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