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jok3333 [9.3K]
3 years ago
11

Please help with this

Mathematics
1 answer:
AveGali [126]3 years ago
6 0

Answer:

x is 67

Step-by-step explanation:

angles on a straight line.

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I don't know how to do this. Any help?
Brut [27]

Answer:

cos 37=x/b (second one)

sin 37= a/b (third one)

tan 37=a/x (sixth one)

Step-by-step explanation:

Cos is defined by the adjacent side over the hypotenuse. Cos 37 would be x/b. Clearly, that is option 2. Sin is defined by opposite over hypotenuse. Sin 37 would be a/b. That is the 3rd option. Tan is defined by opposite over adjacent. Tan 37 would be a/x or the 6th option.

7 0
3 years ago
In a NiCd battery, a fully charged cell is composed of Nickelic Hydroxide. Nickel is an element that has multiple oxidation stat
Westkost [7]

Answer:

P(cell has at least one of the positive nickel-charged options) = 0.83.

P(a cell is not composed of a positive nickel charge greater than +3) = 0.85.

Step-by-step explanation:

It is given that the Nickel Charge Proportions found  in the battery are:

0 ==> 0.17

.

+2 ==> 0.35

.

+3 ==> 0.33

.

+4 ==> 0.15.

The numbers associated to the charge are actually the probabilities of the charges because nickel is an element that has multiple oxidation states that is usually found in the above mentioned states.

a) P(cell has at least one of the positive nickel-charged options) = P(a cell has +2 nickel-charged options) + P(a cell has +3 nickel-charged options) + P(a cell has +4 nickel-charged options) = 0.35 + 0.33 + 0.15 = 0.83.

Or:

P(a cell has at least one of the positive nickel-charged options) = 1 - P(a cell has 0 nickel-charged options) = 1 - 0.17 = 0.83.

b) P(a cell is not composed of a positive nickel charge greater than +3) = 1 - P(a cell is composed of a positive nickel charge greater than +3)

= 1 -  P(a cell has +4 nickel-charged options)  '.' because +4 is only positive nickel charge greater than +3      

= 1 - 0.15

=  0.85

To summarize:

P(cell has at least one of the positive nickel-charged options) = 0.83!!!

P(a cell is not composed of a positive nickel charge greater than +3) = 0.85!!!

8 0
3 years ago
Algebra 1 pls help :)
MaRussiya [10]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the area of a sector that has a radius of 25 mm and has an angle measure of 50°?
Nimfa-mama [501]

The area of the sector is 86.81π mm²

<u>Explanation:</u>

Given:

Radius of the sector, 25mm

Angle, α = 50°

Area of the sector, A = ?

We know:

Area of the sector = \frac{\alpha }{360} X \pi r^2

On substituting the value, we get:

A = \frac{50}{360} X \pi X (25)^2\\\\A = 86.81 \pi mm^2

Therefore, the area of the sector is 86.81π mm²

3 0
4 years ago
*Quadratic equations*<br>solve<br>(i) (x+3)(x-4)=0<br><br>(ii) (2x-3)(x-1) =0​
Ivanshal [37]

Answer:

(i) (x+3)(x-4)=0

  • x+3= 0 ⇒ x= -3
  • x-4= 0⇒ x= 4

(ii) (2x-3)(x-1) =0​

  • 2x-3= 0 ⇒ 2x=3 ⇒ x= 3/2
  • x- 1= 0 ⇒ x= 1
3 0
3 years ago
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