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ANEK [815]
3 years ago
8

find the x-intercepts of the parabola with vertex (-1,-16) and y intercept (0,15), write your answer in this form (x1,y1),(x2,y2

)
Mathematics
1 answer:
LuckyWell [14K]3 years ago
3 0

hello :<span>
<span>the parabola's equation is : f(x) = a(x+1)²+16
the coefficient of the squared expression in the parabola's equation is : a
but ; f(0) = 15 ...  ( </span></span>y-intercepts (0,15) )

15 = a(0+1)²+16
15 =a +16


a=-1
f(x) = -(x-1)²+16

<span> the x-intercepts  when : f(x) =0
</span>-(x-1)²+16=0
(x-1)² =16=4²
x-1 = 4   or x-1 = -4
x=5 or x=-3

 are <span> the x-intercepts 
two points : (5 , 0 )   ; (-3 ; 0)</span>
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