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3 years ago

Please help me asap!!! It's an emergency!!!!!!!

Mathematics

1 answer:

hammer [34]3 years ago

6 0

To solve this question, simply find the percent of loaves of bread to total items, by taking the first loaves of bread and dividing it by the total bakery items. In this case would be, 15 loaves/25 • 100% = 60 %. Do the same calculation for the second loaves of bread. 25 loaves/37 • 100% = 67.567 %.

Now take the difference between the 2 percentages to find the percent increase of loaves of bread, which would be 7.567 %, about 7.6%. Or as a whole number 8%.

The percent increase of the loaves of bread has been 8%.

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List the factor pairs of ac for the trinomial 12x^2-5x-2.

yKpoI14uk [10]

Answer:

(3x - 2) (4x + 1)

Step-by-step explanation:

12x² - 5x - 2

Since the first term has a coefficient, you need to multiply -2 with 12 to get -24.

Two factors that add up to -5 and have a product of -24 are -8 and 3.

12x² - 8x + 3x - 2

Rearrange the expression to find the GCF.

12x² + 3x - 8x - 2

3x (4x + 1) + (-1)2(-4x -1)

3x (4x + 1) - 2 (4x + 1)

(3x - 2) (4x + 1)

3 0

3 years ago

In the diagram, AD=CD=CB and measure of angle A=40°. How many degrees are in angle DCB?

Ad libitum [116K]

Answer:

$20^{\circ}$

Step-by-step explanation:

Consider triangle ACD. This triangle is isosceles triangle, because AD = DC. Angles adjacent to the base AC are congruent abgles, so

$m\angle DAC=m\angle DCA=40^{\circ}$

The sum of the measures of all interiror angles in the triangle is always $180^{\circ},$ then

$m\angle DAC+m\angle DCA+m\angle ADC=180^{\circ}\\ \\40^{\circ}+40^{\circ}+m\angle ADC=180^{\circ}\\ \\m\angle ADC=180^{\circ}-40^{\circ}-40^{\circ}=100^{\circ}$

Angles ADC and BDC are supplementary angles (add up to $180^{\circ}$ ), then

$m\angle BDC=180^{\circ}-100^{\circ}=80^{\circ}$

Consider triangle BCD. This triangle is isosceles triangle because BC = DC. Angles adjacent to the base BD are congruent abgles, so

$m\angle BDC=m\angle DBC=80^{\circ}$

The sum of the measures of all interiror angles in the triangle is always $180^{\circ},$ then

$m\angle DBC+m\angle BDC+m\angle BCD=180^{\circ}\\ \\80^{\circ}+80^{\circ}+m\angle BCD=180^{\circ}\\ \\m\angle BCD=180^{\circ}-80^{\circ}-80^{\circ}=20^{\circ}$

6 0

3 years ago

U matter.

olga2289 [7]

Answer:

thank you <3 I needed this.

Step-by-step explanation:

who's cutting onions??!?!?

6 0

3 years ago

What is the possible arrangement for 22 students

lord [1]

$\bf \stackrel{Permutations}{_nP_r=\cfrac{n!}{(n-r)!}}~\hspace{6em}\stackrel{\textit{22 units arranged in groups of 22}}{_{22}P_{22}=\cfrac{22!}{(22-22)!}} \implies _{22}P_{22}=\cfrac{22!}{0!} \\\\\\ _{22}P_{22}=\cfrac{22!}{1}\implies _{22}P_{22}=22!\implies _{22}P_{22}=1124000727777607680000$

8 0

4 years ago

Which of the following equations is used to find the value of c (the distance to the foci) for an ellipse?

Reika [66]

The equation of ellipse:

$\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1$

The formula of c (the distance to the foci)

$c^2=a^2-b^2\qquad|\text{add}\ b^2\ \text{to the both sides}\\\\c^2+b^2=a^2$

<h3>Answer: c² + b² = a²</h3>

4 0

3 years ago