Answer:
m∠U = 103° and m∠TRS = 6°
Step-by-step explanation:
In the given circle O,
Since, RS║VU, and VR is a transverse,
Therefor, m∠V + m∠R = 180° [Consecutive interior angles]
m∠R + 103° = 180° [m∠R = 103° given]
m∠R = 180° - 103°
m∠R = 77°
Since m∠R = m∠VRT + m∠TRS
77° = 71° + m∠TRS
m∠TRS = 77° - 71° = 6°
Quadrilateral RTUV is a cyclic quadrilateral.
Therefore, m∠U + m∠R = 180°
m∠U + 77° = 180°
m∠U = 180° - 77° = 103°
It is quadratic, because the highest degree for x is 2, x². Expand the expression and you'll see: f(x)=3x²-3x-3x-7
simplify: f(x)=3x²-6x-7
the quadratic term is 3x², the linear term is -6x, the constant is -7
Answer:
if adding its 139 if u subtract then its 11
Step-by-step explanation:
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we know that
When a rectangle with a width of 2.5 feet and a length of 8 feet rotates it makes a cylinder with a radius r = 2.5 ft and a height h = 8 ft
volume of a cylinder=pi*r²*h-----> pi*2.5²*8----> 157 ft³
the answer is157 ft³
Write the set of points from -6 to 0 but excluding -4 and 0 as a union of intervals
First we take the interval -6 to 0. In that -4 and 0 are excluded.
So we split the interval -6 to 0.
Start with -6 and go up to -4. -4 is excluded so we break at -4. Also we use parenthesis for -4.
Interval becomes [-6,-4) . It says -6 included but -4 excluded.
Next interval starts at -4 and ends at 0. -4 and 0 are excluded so we use parenthesis not square brackets
(-4,0)
Now we take union of both intervals
[-6,-4) U (-4,0) --- Interval from -6 to 0 but excluding -4 and 0
