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3 years ago

Which expression is equivalent to 2^6 x 2^-4 / 2^7

2 answers:

6 0

2^6 * 2^(-4) / 2^7

= 2^6 * ( 1 / 2^4 ) * ( 1 / 2^7 )

= 2^6 * ( 1 / 2^11 )

= 2^(6-11)

= 2^(-5)

= 1 / 2^5

= 1 / 32

the answer is 1 / 32

nata0808 [166]3 years ago

6 0

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A bag with 8 marbles is shown below. (The 8 marbles are red.) A marble is

Degger [83]

Answer:

Step-by-step explanation:

There are 8 marbles.

All marbles are red.

p(red) = 8/8 = 1

Answer: 1

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2 years ago

Read 2 more answers

Jared is scheduled to work for 5/6 of an hour at the school fair. He has already worked 1/3 of an hour. How much longer does he

Cloud [144]

The answer is D

Because
5/6 - 1/3
=5/6 - 2/6
=3/6
=1/2h

4 0

3 years ago

Read 2 more answers

The volume of air inside a rubber ball with radius r can be found using the function V(r)= 4/3pier^3 what does V(5/7) represent?

CaHeK987 [17]

Answer:

Step-by-step explanation:

I can tell you what it represents, but not what it means. Or maybe the units.

V(5/7) means that wherever you see an r on the right hand side, you put in 5/7 where the R is.

V = 4/3 * pi * r^3

V(5/7) = 4/3 * 3.14 * (5/7)^3

V(5/7) = 4/3 * 3.14 * 125 / 343

V(5/7) = 4/3 * 3.14 * 0.3644

V(5/7) = 1.526 cubic units (of whatever the units of 5/7 were to begin with)

6 0

3 years ago

Write 0.87878787.... as a fraction

irinina [24]

Step-by-step explanation:

To write 0.87878787 as a fraction you have to write 0.87878787 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.

0.87878787 = 0.87878787/1 = 8.7878787/10 = 87.878787/100 = 878.78787/1000 = 8787.8787/10000 = 87878.787/100000 = 878787.87/1000000 = 8787878.7/10000000 = 87878787/100000000

And finally we have:

0.87878787 as a fraction equals 87878787/100000000

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5 0

3 years ago

Give an example of each of the following, or state that such a request is impossible by referencing the proper theorem(s): (a) s

aev [14]

Answer:

There are many examples for the first request, but none for the second.

Step-by-step explanation:

a) There is a theorem which states that the sum of two convergent sequences is convergent, so any pair of convergent sequences (xn), (yn) will work (xn=1/n, yn=2/n, xn+yn=3/n. All of these converge to zero)

If you meant (xn) and (yn) to be both divergent, we can still find an example. Take (xn)=(n²) and (yn)=(1/n - n²). Then (xn) diverges to +∞ (n² is not bounded above and it is increasing), (yn) diverges to -∞ (1/n -n² is not bounded below, and this sequence is decreasing), but (xn+yn)=(1/n) converges to zero.

b) This is impossible. Suppose that (xn) converges and (xn+ýn) converges. Then (-xn) converges (scalar multiples of a convvergent sequence are convergent). Now, since sums of convergent sequences are convergent, (xn+yn+(-xn))=(yn) is a convergent sequence. Therefore, (yn) is not divergent and the example does not exist.

5 0

4 years ago