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3 years ago

How do you break apart the factor 42 using place value?

Mathematics

1 answer:

worty [1.4K]3 years ago

6 0

Hey there!☺

Let's break apart 42.

The 4 is in the tens. The 2 is in the ones.

Place Value starting from Thousands

Thousands Hundreds Tens Ones

_________ ________ ____ _____

4 2

So this is how we break up numbers using place value.

Hope this helps!

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For what values of a does the equation a+x= 1+xa^2 have no solution?

Anton [14]

Answer:

We have the equation

$a+x= 1+xa^2$

we leave the terms with x on the left side of the equation and the independent terms on the right side.

$x-xa^2=1-a\\(1-a^2)x=1-a\\$

resolving for x we have that

$x=\frac{1-a}{1-a^2}$

Since we need that the equation doesn't have solution, then it is necessary that the denominator of x be 0 and this occur when $1-a^2=0\\1=a^2\\a=\pm1$

Then, for $a=\pm1$ the equation hasn't solution

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3 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$

The degrees of freedom for this sample size are:

$df=n-1=50-1=49$

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=2.01 \cdot 0.305=0.61$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95$

The 95% confidence interval for the mean is (5.73, 6.95).

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3 years ago

2 345 000 000 in scientific notation

grigory [225]

2.345 * 10^9 . Hope this helps

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3 years ago

How many places do you need to move the decimal to the left to write the

Vlad [161]

Answer:

Step-by-step explanation:

the decimal always goes between the numbers that arent 0s

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2 years ago

Please help. 20 points and brainliest.

storchak [24]

Answer:

choce 3

Step-by-step explanation:

you can add n = 1,2,3,4 ....

you will receive the values as 1, 1/2, 1/4, 1/7

........

a⁰ = 1

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3 years ago