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zheka24 [161]
3 years ago
8

A=2BD+2BC solve for B

Mathematics
2 answers:
Genrish500 [490]3 years ago
7 0

Answer:

B=\frac{A}{2(C+D)}

Step-by-step explanation:

A=2BD+2BC

We can also write this by taking out 2B common:

A=2B(C+D)

Dividing both sides by C+D;

=> 2B=\frac{A}{C+D}

Dividing both sides by 2;

=> B=\frac{A}{2(C+D)}

Hence, the value of B is :

B=\frac{A}{2(C+D)}

Butoxors [25]3 years ago
6 0
Try two. I'm not sure what the answer is
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Camilla baked 15 cookies with 3 scoops of flour. How many scoops of flour does Camilla need in order to bake 20 cookies? Solve u
omeli [17]

Answer:

camilla needs 4 scoops of flow because 3 is related to 15 bc "5x3=15" and that gives us to only need 1 more cup to get 20 cookies

7 0
2 years ago
In the figure below, lines L and M are parallel and line AB = line BC = line AC. What is the measure of the exterior angle
Kryger [21]

Answer:

120º

Step-by-step explanation:

angles of an equilateral triangle are equal so..

180 ÷ 3 = 60º

to get the exterior m⦣C

180 - interior m⦣C = exterior m⦣C

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6 0
2 years ago
URGENT
Nastasia [14]

Answer:

x45

Step-by-step explanation:

8 0
2 years ago
Classify the system of equations and identify the number of solutions.
mestny [16]

Answer:

x = all real numbers

Step-by-step explanation:

first you need to solve the first equation to figure out what y is.

4x - y = 2

<em>add y to both sides of the equation</em>

4x = 2 + y

s<em>ubtract 2 from both sides of the equation</em>

4x - 2 = y

now that you know what y is, you can substitute it in the next equation.

3y = 12x - 6

3(4x - 2) = 12x - 6

<em>open the parenthesis </em>

12x - 6 = 12x - 6

<em>subtract 12x from both sides of the equation</em>

-6 = -6

regardless of what x is, -6 will always equal -6.

so, the answer is all real numbers.

6 0
3 years ago
Find the positive value of x in the geometric sequence 7x-2,4x+4,3x
Goryan [66]
Hello,


Let's assume k the ratio.

&#10; \left \{ {{3x=k*(4x+4)} \atop {4x+4=k*(7x-2)}} \right. \\\\&#10; \left \{ {{3x-4kx=4k} \atop {4x-7kx=-2k-4}} \right. \\\\&#10; \left \{ {{x(3-4k)=4k} \atop {x(4-7k)=-2k-4}} \right. \\\\&#10; \left \{ {{x=\dfrac{4k}{3-4k} \atop {x=\dfrac{-2k-4}{4-7k} \right. \\\\&#10;&#10;\dfrac{4k}{3-4k}=\dfrac{-2k-4}{4-7k}\\\\&#10;&#10;36k^2-6k-12=0\\&#10;6k^2-k-2=0\\&#10;&#10;\boxed{k= \dfrac{2}{3} \ or\ k= -\dfrac{1}{2}}\\\\&#10;&#10;x=\dfrac{4*\dfrac{2}{3} }{3-4*\dfrac{2}{3} }=8\\&#10;x=\dfrac{4*\dfrac{-1}{2} }{3-4*\dfrac{-1}{2} }=-\dfrac{2}{5}\\&#10;&#10;&#10;&#10;&#10;&#10;

\boxed{x= 8 \ or\ x= -\dfrac{2}{5}}\\\\





5 0
2 years ago
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