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3 years ago

Which of the following is a postulate?

Mathematics

2 answers:

creativ13 [48]3 years ago

7 0

Planes postulate is the answer to your question because it needs to have at least 2 points

Zepler [3.9K]3 years ago

5 0

Answer:

Collinear Lines Postulate

Step-by-step explanation:

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Solve |x|>5 A. {-5,5} B. { x|-5 < x < 5 } C. { x|x < -5 or x > 5}

Marizza181 [45]

Solve |×|> 5

×>5 or ×<-5

C.{×<-5 or ×> 5}

8 0

3 years ago

X/2 + 4/5 = 1/2 solve for x

Flura [38]

Answer:

Step-by-step explanation:

x/2 + 4/5 = 1/2

×2 ×2

x + 8/5 = 1

-8/5 -8/5

x = 5/5 - 8/5

x = -3/5

3 0

4 years ago

An athlete eats 0.4kg of protein per week while training. How much protein will she eat during 6 weeks of training?

kolezko [41]

0.4kg per week. so 0.4kg x 6 weeks is 2.4kgs

7 0

3 years ago

A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$

$\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3$

$\dfrac{F_m}{F_p} = \left( \left\dfrac{1}{17} \right)^3$ = (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ ≈ 0.0002.

5 0

3 years ago

Will give brainlessst if you answer plsssss

son4ous [18]

Answer:

he is right

Step-by-step explanation:

because If they're in fraction form, set them equal to each other to test if they are proportional. Cross multiply and simplify. If you get a true statement, then the ratios are proportional!

4 0

3 years ago