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3 years ago

How do you tell whether the percent of a number will be greater than, less than, or equal too the number

1 answer:

8 0

If the tens are greater for one number then that number will be greater. Parent Note: ... The tens are equal so we need to compare the ones.

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I wonder if I did #9 right and I’m having trouble with #10

yaroslaw [1]

Let's see....

QUESTION: Add. Write your answer as a mixed number in simplest form.

$6 \frac{7}{9} + 9 \frac{8}{9}$

1. Rewriting our equation with parts separated

 $=6+ \frac{7}{9} +9+ \frac{8}{9}$

2. Solving the whole number parts

 $6+9=15$

3. Solving the fraction parts

 $\frac{7}{9} + \frac{8}{9} = \frac{15}{9}$

4. Reducing the fraction part, 15/9,

 $\frac{15}{9} = \frac{5}{3}$

5. Simplifying the fraction part, 5/3,

 $\frac{5}{3} = 1\frac{2}{3}$

6. Combining the whole and fraction parts

 $15+1+ \frac{2}{3} =16 \frac{2}{3}$

ANSWER: $16\frac{2}{3}$

Hope that helps!

8 0

3 years ago

Read 2 more answers

Solis have 30 cupcake.and she have 12 more of the cupcakes.how many in all?how many in total do solis have

prohojiy [21]

42 you just add 30 and 12

7 0

3 years ago

The dimensions of a rectangular prism are shown in the diagram below. Write an expression that represents the volume of the rect

ValentinkaMS [17]

Answer:

$V=(a^{4})(b^{6})\ units^3$

Step-by-step explanation:

we know that

The volume of a rectangular prism is equal to

$V=LWH$

In this problem we have

$L=ab^2\\W=ab^3\\H=a^2b$

substitute

$V=(ab^2)(ab^3)(a^2b)$

Applying property of exponents

$x^{m} x^{n}x^{r} =x^{m+n+r}$

$V=(a^{4})(b^{6})\ units^3$

7 0

3 years ago

Find the Derivative y’ implicitly.

Brums [2.3K]

$e^{x^2y} - e^y = e^y(e^{x^2} - 1) = x$

We should ISOLATE x

$e^y= \frac{x}{e^{x^2} - 1}$

Find the Natural Log of Both Sides to Make the Left Side "y"

$y = ln(\frac{x}{e^{x^2}-1})$

Now, FIND THE DERIVATIVE Using Chain Rule!!!

$y' = \frac{1}{\frac{x}{e^{x^2}-1}} * \frac{(1(e^{x^2}-1) - x(2x*e^{x^2})}{(e^{x^2}-1)^2}= {\frac{e^{x^2}-1}{x}}* \frac{(1(e^{x^2}-1) - x(2x*e^{x^2})}{(e^{x^2}-1)^2} = {\frac{1}{x}}* \frac{(1(e^{x^2}-1) - x(2x*e^{x^2})}{(e^{x^2}-1)} = {\frac{1}{x}}* \frac{(e^{x^2}-1 - 2x^2e^{x^2})}{(e^{x^2}-1)}$

3 0

2 years ago

Please help me answer this :) Explain your answer Will give brainiest

lora16 [44]

Answer:

A: Store A will cost about $1.28 less

Step-by-step explanation:

Okay, let's find the unit rate of cost. To find that for store A, we divide 7.26 by 3, which gets us 2.42. For store B, we need to look for the first intersection. We find that at (20, 50). Let's divide 50 by 20. That gets us 2.50. Let's multiply 2.42 and 2.50 by 16. That gets us 38.72 for store A and 40 for store B. Let's subtract 38.72 from 40. That gets us 1.28. That means store A costs $1.28 less than store B. That makes our answer A.

4 0

2 years ago

Read 2 more answers