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svetoff [14.1K]
3 years ago
5

Solve for x: 1/abx = 1/a + 1/b + 1/x

Mathematics
1 answer:
AnnZ [28]3 years ago
6 0

Answer:

Value of x = \frac{1-ab}{a+b}

Step-by-step explanation:

Given that: \frac{1}{abx} = \frac{1}{a} +\frac{1}{b} +\frac{1}{x}

Solve for x;

Taking LCM of a , b and x is abx.

\frac{1}{abx} =\frac{bx+ax+ab}{abx}

Multiply both sides by abx we get;

1 = bx+ax+ab

Subtract ab from both sides we get;

1-ab = bx + ax

Using distributive property: a\cdot (b+c) = a\cdot b +a \cdot c

1- ab = x(a + b)

Divide both sides by a+b we get;

x = \frac{1-ab}{a+b}

Therefore, value of x is; \frac{1-ab}{a+b}

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3 years ago
What is the factored form of _________?
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Answer:

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Step-by-step explanation:

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3 years ago
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2 years ago
What is the value of v? 4/5(v−7)=2
Nostrana [21]
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3 0
3 years ago
Read 2 more answers
What are the coordinates of the endpoints of the midsegment for DEF that is parallel to DE
Nutka1998 [239]

Answer:

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right),  \left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

Step-by-step explanation:

Let points D, E and F have coordinates (x_D,y_D),\ (x_E,y_E) and (x_F,y_F).

1. Midpoint M of segment DF has coordinates

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right).

2. Midpoint N of segment EF has coordinates

\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.

6 0
3 years ago
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