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svetoff [14.1K]
3 years ago
5

Solve for x: 1/abx = 1/a + 1/b + 1/x

Mathematics
1 answer:
AnnZ [28]3 years ago
6 0

Answer:

Value of x = \frac{1-ab}{a+b}

Step-by-step explanation:

Given that: \frac{1}{abx} = \frac{1}{a} +\frac{1}{b} +\frac{1}{x}

Solve for x;

Taking LCM of a , b and x is abx.

\frac{1}{abx} =\frac{bx+ax+ab}{abx}

Multiply both sides by abx we get;

1 = bx+ax+ab

Subtract ab from both sides we get;

1-ab = bx + ax

Using distributive property: a\cdot (b+c) = a\cdot b +a \cdot c

1- ab = x(a + b)

Divide both sides by a+b we get;

x = \frac{1-ab}{a+b}

Therefore, value of x is; \frac{1-ab}{a+b}

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3 1/2 - 4 2/5<br> how do i do this?
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Ok so first you would have to turn them into improper fractions which is

3 \frac{1}{2\\} = \frac{7}{2} and 4 \frac{2}{5} = \frac{22}{5}

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Step-by-step explanation:

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