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Svetach [21]
4 years ago
5

Two-fifths of the girls signed up to play softball. An equal number of girls signed up to play pitcher, infield, and outfield. W

hat fraction of girls in the school signed up to play outfield?
Any help appreciated, thank you!
Mathematics
2 answers:
Yuliya22 [10]4 years ago
5 0

Answer: Hello mate!

You know that 2/5 of the total girls signed up to play softball.

an equal number of the girls signed up to play pitcher, infield, and outfield.

this means that we could divide the 2/5 initial group into 3 equal smaller groups (one for each position)

then the fraction of girls that signed up to play outfield is:

(1/3)*(2/5) = 2/15

then 2/15 of the total girls signed to play softball in the position of outfield.

Natali [406]4 years ago
3 0
Okay so lets look at this.

So we have 5/5 girls.

2/5 of them are playing softball.  An equal number of girls signed up to play pitcher, infield, and outfield.  This means that each one is 1/3.

So out of 2/5 of the girls, there is 1/3 of the 2/5 that signed up to play outfield.

The answer can be solved with multiplication of fractions.

2/5 * 1/3 is 2/15.  So 2/15 of the girls in the school signed up to play outfield.

Answer: 2/15 or 0.133
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Step-by-step explanation:

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grandymaker [24]

Given :

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Solution :

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3 years ago
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In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample. To determine
zimovet [89]

Answer:

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(b)  0.0111

(c)  0.0105

(d)  0.0006

Step-by-step explanation:

Given that:

In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample.

Suppose that the number of CFUs that appear after incubation follows a Poisson distribution with mean μ = 15.       &;

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We can determine the mean number of CFUs that appear on a 25cm² area of the plate as follows;

75cm²/25cm² = 3

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mean  μ = 15  

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= P(X < 4)

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c) Repeat the probability calculation in part (b) but now use the normal approximation.

Let assume that the mean and the variance of the poisson distribution are equal

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(d)  Find the difference between this value and your answer in part (b).

So;

the difference between the value in part c and part b is;

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