11. You’ve done it correctly
12. Let x^2=y
y^2+13y+40=0
(y+8)(y+5)=0
y=8, 5
Since y=x^2
x^2=8 x^2=5
x=+/-√5 x= +/-2√2
13. x^4-x^2-x^2-8=0
x^4-2x^2-8=0
let x^2=y
Y^2-2y-8=0
(y-4)(y+2)=0
y=4, -2
Since y=x^2
X^2=4 X^2=-2
X= +/- 2 This wouldn’t be a real solution
14. It’s pretty much the same process, just substitute y in for x^2. If you’re confused feel free to ask and I can do it, or you can put it through Photomath
15. You’re on the right track so I’m just going to continue from where you left off
x^2(4x+5)-4(x+5)=0
(x^2-4)(4x+5)=0
x= +/- 2 4x=5
x=5/4 or 1 1/4
Hope this helped :)
I believe it is the second option.
Hope this helps :)
Answer: -842
Step-by-step explanation:
To find n95, we have to use the equation aₙ = d * n + a₁ - d
a₁ is the first term, which here is 4. d is the common difference, which we can find out but seeing what we can add pr subtract from 4 to -5 which also equals -5 to -14, in this equation, the common difference would be -9 as it goes down by 9 every term. Once we plug these into the equation, we get
a₉₅ = -9 * n + 4 - (-9)
We can solve this for - aₙ = -9n + 13
Now that we have our equation to find a term, we can plug in n for 95 for
-9(95) + 13
Which equals -842
Y=x^3
X cubed
Hope this helps
