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Svetllana [295]
3 years ago
6

Sam divided A rectangle into 8 congruent rectangles that each have the area shown. what is tge area of tge rectangle befoe sam d

ivided it
Mathematics
1 answer:
aniked [119]3 years ago
3 0

No area is shown. So befoe sam divided it,
the area of tge original rectangle was . . .

     8 x 0  =  zero .


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Solve this equation -9h - 6 + 12h + 40 = 22
schepotkina [342]

-9h - 6 + 12h + 40 = 22\\\\3h=-12\\\\h=-4

5 0
2 years ago
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Use the equation 2,401 = 76 – 2x. What power of 7 is 2,401?
zaharov [31]
Comment
I'm going to take a guess at this and say what you meant is  2401 = 7^(6 - 2x)

Step One
Find out the power of 7 that will equal 2401. 
You could do it like this.
7^y = 2401 and just guess at some values.

y      7^y
1      7
2      49
3      7 * 7 * 7 = 343
4      7 * 7 * 7 * 7 = 2401  So the answer is 4

7^4 = 2401

Step 2 
Equate the powers.
2401 = 7^(6 - 2x)
7^4 = 7^ (6 - 2x)
4 = 6 - 2x  Subtract 6 from both sides.
4 - 6 = - 2x 
-2 = - 2x divide by - 2
-2/-2 = x
x = 1 <<<<<<<<<<<<<answer

7 0
3 years ago
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Factor out the greatest common factor. 10a3b−6a2b2
podryga [215]

Answer:

2a^2b(5a-3b)

If not then the other way is

5a-3b

Step-by-step explanation:

The GCF of 10a^3b and -6a^2b^2 is 2a^2b

So divide by that you will get

2a^2b(5a-3b)

4 0
3 years ago
ANSWER IF YOU KNOW THE ANSWER!!! I WILL GIVE BRAINLIEST BTW!!!!!!!!!!!!!
AURORKA [14]

im pretty sure its c

7 0
2 years ago
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5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.
s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of <em>(</em><em>124</em><em> </em><em>and</em><em> </em><em>244</em><em>)</em><em> </em>and <em>(</em><em>4424</em><em> </em><em>and</em><em> </em><em>2111</em><em>)</em><em> </em>are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

<em>#initialize</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>named</em><em> </em><em>gcd</em><em> </em><em>which</em><em> </em><em>takes</em><em> </em><em>in</em><em> </em><em>two</em><em> </em><em>parameters</em><em> </em>

if a>b:

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>greater</em><em> </em><em>than</em><em> </em><em>b</em>

return gcd (b, a)

<em>#if</em><em> </em><em>true</em><em> </em><em>interchange</em><em> </em><em>the</em><em> </em><em>Parameters</em><em> </em><em>and</em><em> </em><em>Recall</em><em> </em><em>the</em><em> </em><em>function</em><em> </em>

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

<em>#even</em><em> </em><em>numbers</em><em> </em><em>leave</em><em> </em><em>no</em><em> </em><em>remainder</em><em> </em><em>when</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>2</em><em>,</em><em> </em><em>checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>are</em><em> </em><em>even</em><em> </em>

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>odd</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>even</em><em> </em>

return gcd(a, b/2)

else :

return gcd(a, b-a)

<em>#since</em><em> </em><em>it's</em><em> </em><em>a</em><em> </em><em>recursive</em><em> </em><em>function</em><em>,</em><em> </em><em>it</em><em> </em><em>recalls</em><em> </em><em>the function</em><em> </em><em>with </em><em>new</em><em> </em><em>parameters</em><em> </em><em>until</em><em> </em><em>a</em><em> </em><em>certain</em><em> </em><em>condition</em><em> </em><em>is</em><em> </em><em>satisfied</em><em> </em>

print(gcd(124, 244))

print()

<em>#leaves</em><em> </em><em>a</em><em> </em><em>space</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>output</em><em> </em>

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

6 0
2 years ago
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