Answer:
66 I think might he wrong
Step-by-step explanation:
I'm not sure if its right
Answer:
a=2x-b
Step-by-step explanation:

Answer: W = -4, -4
Z = 3, -6
Step-by-step explanation:
The quadratic formula is ![\frac{-b+-\sqrt[2]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%2B-%5Csqrt%5B2%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
and in the equation ax^2+bx+c=0
so now all you have to do is substitute the numbers into the quadratic formula
Assuming that <span>4^2-6(2^x)-16=0 is correct, we can rearrange it as:
</span><span>-6(2^x) + 4^2 - 16=0
Are you sure it's not </span>6(2^x) + 4^2 - 16=0 ?
If 6(2^x) + 4^2 - 16=0 is correct, then
6(2^x) + 4^2 - 16=16 - 16 = 0, that is, 6(2^x) = 0. Then x = 0 (answer)