Of you have 3 squared you get 9 then 2 times -2 is -4. then you add them 9=-4 which would be ...A: 5
        
                    
             
        
        
        
9×1=09
9×2=18
9×3=27
as you can see the algorithm would most likely be deducting one from the second digit and adding it to the first digit
        
                    
             
        
        
        
Okay so divide 56 by 14 and so x = 4
        
             
        
        
        
Answer:
x = 5/(a-b+3)
Step-by-step explanation:
ax+3x=bx+5
Collect all the terms that has x:
ax-bx+3x = 5 (Subtracting bx both sides)
Take out the x!
x(a-b+3) =5
Divide (a-b+3) both sides to solve for x
x = 5/(a-b+3)
Hope this helps!
Would really appreicate the brainliest!