In calculus, we use derivatives to find the instantaneous rate of change at any point on a graph. To find the average rate of change, we just find the slope of the secant line that intercepts two points on the graph.
We find slope with the following equation:
In this case, we are looking for the slope from x = -1 to x = 1. We have both x values, so next we need the y values.
F(-1) = (-1)^2 - (-1) - 1 = 1
F(1) = (1)^2 - (1) - 1 = -1
Now plug in the x and y values to find the slope:
The answer is -1.
Hey There!
If i got this down right,
An = A1 + (n - 1)d
Sn = A1 + A2 + A3 + ... + An
A1 is given by
Sn = n (A1 + An) / 2
For Example
An = A1 + (n - 1)d
= 6 + 3 (n - 1)
= 3 n + 3
n = 50
Hope This Helps!!!
rewrite -1 1/3 as a decimal: -1.5
-2.1 - x = -1.5
Subtract -2.1 From both sides:
X = -1.5 - -2.1 = -1.5 + 2.1
X = 0.6
Answer: B. 0.6
You might have made an error the first time you solved for x. I got x = -0.5.
When you have your log base 4, the way you cancel that out is by making 4 the base on both sides, so you get 4^(log4) to reduce to 1, and you're left with:
2x + 3 = 4^(1/2) ... Simplify
2x + 3 = 2
2x = -1
x = -1/2
If you plug that back in, everything checks out. Maybe double check your use of logarithm/exponent properties?
Answer:
y = 0
Step-by-step explanation:
The given sinusoidal equation is 
The general form of the sin function is presented as follows;
y = A·sin(B·(x - C)) + D
Where;
A = The amplitude
The period, T = 2·π/B
The frequency, f = B/2·π
C = The horizontal shift
D = The vertical shift
By comparison with the given sine function, we have;
The amplitude, A = 2
The frequency, f = B/2·π = π/2/(2·π) = 1/4
The frequency, f = 1/4 Hz
C = The horizontal shift = 3/(π/2) = 6/π
The vertical shift, D = 0
Given that the mid line of the parent function, sin(x), is the line y = 0, and that the vertical shift is 0, the midline of the function, , is therefore, the line;
y = 0.
