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3 years ago

Can someone please help me with this

Mathematics

1 answer:

BARSIC [14]3 years ago

3 0

I’m not 100% but my best guess is 20.

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EASY MATH QUESTION HELP! Under the Angle Addition Postulate, which equation would be valid?

Licemer1 [7]

Answer:

B for the first one , and C for the second

Step-by-step explanation:

for the first question DEG which is 60, and GEF which is 120, would equal to 180 degrees, which would be DEF because its a linear pair.

For the second question the are alternate exterior angles, so the are opposite of each other and on the outside.

6 0

2 years ago

Read 2 more answers

Drag each equation to show if it could be a correct first step to solving the equation 3(6+x)=24

kakasveta [241]

Use the distributive property.

3(6 + x) = 24

18 + 3x = 24

3x = 6

x = 2

5 0

2 years ago

Read 2 more answers

The equation t^3=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A

ankoles [38]

Answer:

2√2

Step-by-step explanation:

We can find the relationship of interest by solving the given equation for A, the mean distance.

<h3>Solve for A</h3>

$T^3=A^2\\\\A=\sqrt{T^3}=T\sqrt{T}\qquad\text{take the square root}$

<h3>Substitute values</h3>

The mean distance of planet X is found in terms of its period to be ...

$D_x=T_x\sqrt{T_x}$

The mean distance of planet Y can be found using the given relation ...

$T_y=2T_x\\\\D_y=T_y\sqrt{T_y}=2T_x\sqrt{2T_x}=(2\sqrt{2})T_x\sqrt{T_x}\\\\D_y=2\sqrt{2}\cdot D_x$

The mean distance of planet Y is increased from that of planet X by the factor ...

2√2

8 0

1 year ago

Solve linear equations -4(b+3)-12=2b-16+5b

daser333 [38]

Answer:

$Exact form:b=-\frac{8}{11}\\Decimal form: b=-0.72727272727272727272$

Step-by-step explanation:

$-4(b+3)-12=2b-16+5b$

$-4b-12-12=2b+5b$

$-4b-24=7b-16$

$-4b=7b+8$

3 0

3 years ago

Read 2 more answers

What is the area of the semicircle?

Serggg [28]

Step-by-step explanation:

$Area (semi-circle)= \frac{r^2\pi }{2}$

$A = \frac{(11)^2\pi }{2}$

$A=\frac{121\pi }{2}$

$A=\frac{379.94}{2}$

$A=189.97$

The area of the semi-circle is 189.97

6 0

2 years ago