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snow_tiger [21]

3 years ago

8

which ratio of dimensions of a circle equals pi a. circumference to radius b.circumference to diameter c. areato radius d. area

to diameter

1 answer:

Nutka1998 [239]3 years ago

3 0

The constant pi is by definition the ratio of the circumference to the diameter.

π=C/d

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What is the area, in square centimeters, of the shaded part of the rectangle

mojhsa [17]

Answer:

I honestly dont know I just need the points

8 0

3 years ago

Write the equation - 3x + 2y = 7 in slope-intercept form.

VikaD [51]

Answer:

The answer is :

$y = \frac{3}{2} x + \frac{7}{2}$

Step-by-step explanation:

Given that the slope-intercept form is represented by y = mx + b. So you have to rearrange the equation :

$- 3x + 2y = 7$

$2y = 3x + 7$

$y = \frac{3}{2} x + \frac{7}{2}$

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3 years ago

Read 2 more answers

How to calculate how many times greater a number is?

stiv31 [10]

Division is ur answer..

examples...

300 and 30......300/30 = 10....so 300 is 10 times greater then 30.

5000 and 50....5000/50 = 100...so 5000 is 100 times greater then 50.

70 and 20 ......70/20 = 3.5 ....so 70 is 3.5 times bigger then 20

5 0

3 years ago

Find 10th term of a geometric sequence whose first two terms are 2 and -8. Please answer!!

Shalnov [3]

Answer:

The 10th term is -524,288

Step-by-step explanation:

The general format of a geometric sequence is:

$a_{n} = r*a_{n-1}$

In which r is the common ratio and $a_{n+1}$ is the previous term.

We can also use the following equation:

$a_{n} = a_{1}*r^{n-1}$

In which $a_{1}$ is the first term.

The common ratio of a geometric sequence is the division of the term $a_{n+1}$ by the term $a_{n}$

In this question:

$a_{1} = 2, a_{2} = -8, r = \frac{-8}{2} = -4$

10th term:

$a_{10} = 2*(-4)^{10-1} = -524288$

The 10th term is -524,288

6 0

3 years ago

Consider the two triangles shown. Which of the triangle congruence theorems could be used to prove the triangles congruent witho

Georgia [21]

Answer: AAS

Step-by-step explanation:

In the given triangles, there are two angles such as $84^{\circ}$ and $39^{\circ}$ and one non included side as 16 cm of both triangles are equal or congruent.

Thus, by AAS postulate of congruence both the triangles are congruent without establishing any additional information.

<em>The AAS postulate says that if two angles and the non-included side one triangle are congruent to two angles and the non-included side of another triangle, then these two triangles are congruent.</em>

7 0

4 years ago