Answer:
The cost of the 28 units sold is $548
Explanation:
In the given question,
On March 1 it purchase 12 units for $15 = 12 units × $15 = $180
On March 2 it purchase 12 units for $24 = 12 units × $24 = $288
On March 6 it purchase 7 units for $20 = 7 units × $20 = $140
And, on march it sold 28 units for $63 each
The 28 units could be taken from
12 × $15 = $180
12 × $24 = $288
And remaining 4 units × $20 = $80
So, the total cost of units sold = $180 +$288 +$80 = $548
Answer: a) Information that is relevant to the case.
Explanation:
A legitimate reason for this examination of document is because it's the document that's involved or relevant to the case.
Answer:
The value of X that gives maximum profit is <u>15.92</u>.
Explanation:
Before answering the question, Y and Revenue (R) given in the question are first correctly restated as follows:
Cost = Y = 11 + 0.4X + 0.29X^2 .......................................... (1)
Revenue = R = 16X − 0.2X^2 .............................................. (2)
Differentiating each of equations (1) and (2) with respect to X to obtain marginal cost (MC) and marginal revenue (MR), we have:
dY/dX = MC = 0.4 + 0.58X .................................................. (4)
dR/dX = MR = 16 - 0.4X ....................................................... (5)
In production theory, profit is maximized when MR = MC. Therefore, we equate equations (4) and (5) and solve for X as follows:
0.4 + 0.58X = 16 - 0.4X
0.58X + 0.4X = 16 - 0.4
0.98X = 15.6
X = 15.6 / 0.98
X = 15.92
Therefore, the value of X that gives maximum profit is <u>15.92</u>.
Answer:
Full question: <em>On their birthdays, employees at a large company are permitted to take a 60-minute lunch break instead of the usual 30 minutes. Data were obtained from 10 randomly selected company employees on the amount of time that each actually took for lunch on his or her birthday. The company wishes to investigate whether these data provide convincing evidence that the mean time is greater than 60 minutes. Of the following, which information would NOT be expected to be a part of the process of correctly conducting a hypothesis test to investigate the question, at the 0.05 level of significance?</em>
<em>Answe</em><em>r: Since that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes. </em>
Explanation:
<em>From the given question let us recall the following statements:</em>
<em>Employees at a large company are permitted to take a 60-minute Lunch break instead of the 30 minutes.</em>
<em>Data was gotten from = 10 randomly selected company employees on the amount of time that each actually took for lunch on his or her birthday</em>
<em>Given that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes.</em>
<em>The company tries to investigate the data to know that the mean is greater than 60 minutes</em>
<em>the next step is to find the process of correctly conducting a hypothesis test to investigate the question, at the 0.05 level of significance</em>
<em>Therefore,</em>
<em>Since that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes. </em>
<em>Or</em>
<em>The P-value> 0.05</em>
<em>The mean time is not greater than 60 minutes</em>
Answer:
The right solution will be "trade-offs".
Explanation:
- An exploration of trade-offs is a way of choosing between opposing alternatives.
- Even though unofficial market experiments are often conducted essentially by logically evaluating options and making an informed decision, systematic trade experiments become beneficial in refining and reasserting opinions as well as eliminating prejudice from the course of action.
