Which of the following are congruent? ΔSTV and ΔTVU ST and TV ∠STV and ∠SVT UV and SV ∠U and ∠S ∠TVU and ∠SVT
2 answers:
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We analyze the linear function to find that it has equation 
. Drawing the line, we find that it will intersect the circle at negative and positive x-coordinates.
We can prove this by substituting into the given equation:
Hence,
or 
, so there are both positive and negative values for 
.
We can prove this by substituting
Hence,
Answer:
Proportionality constant =
Step-by-step explanation:
Let y ∝ x
y = kx
Here, k = proportionality constant
From the table attached,
If x = 2 and y = 3,
3 = 2k
k =
If x = 4 and y = 6,
6 = 4k
k =
k =
Since, k = is constant in every condition, table represents the proportional relation with proportionality constant
.
The usual substitutions can be used:
x = r·cos(θ)
y = r·sin(θ)
These give
2r·cos(θ) -2r·sin(θ) = 3
Solving for r, we get the desired equation:
r = 3/(2·(cos(θ) - sin(θ)))
x = r·cos(θ)
y = r·sin(θ)
These give
2r·cos(θ) -2r·sin(θ) = 3
Solving for r, we get the desired equation:
r = 3/(2·(cos(θ) - sin(θ)))