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kow [346]
4 years ago
8

How do I do this equation?

Mathematics
1 answer:
Natasha2012 [34]4 years ago
3 0
Multiply 5×3 and then divide 200÷4
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Evaluate the limit of lim/n->infinity 6n^2+5/3n^2
castortr0y [4]

we are given

\lim_{n \to \infty} \frac{6n^2+5}{3n^2}

we can see that

degree of numerator = degree of denominator =2

so, we can divide both numerator and denominator by n^2

and we get

\lim_{n \to \infty} \frac{(6n^2+5)/n^2}{(3n^2/n^2)}

\lim_{n \to \infty} \frac{(6n^2/n^2)+(5/n^2)}{(3n^2/n^2)}

now, we can simplify it

\lim_{n \to \infty} \frac{6+(5/n^2)}{3}

now, we can plug n=inf

=  \frac{6+(5/(\infty))}{3}

=  \frac{6+0}{3}

=  \frac{6}{3}

=  2...............Answer

6 0
3 years ago
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Esma has a box that is 20 cm wide 10 cm high, and 10 cm deep she wants to fill the box with packages that are 5 cm wide 2 cm hig
anastassius [24]

Answer:

Esma can fit 3 packages in the box because 20+10+10=30 and 5+2+2=9 so if you add up 9 three times you get 27 and that is the closest number you can get before going over.

Step-by-step explanation:

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Use this graph and the shapes shown to complete the tasks in this activity.
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Answer: A reelection across the Y axis, then a reflection across the X axis.

Step-by-step explanation:

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