Ask question

Ask question

All categories

2 years ago

8

An average ant is 1/4 inch long. An average aphid is 3/32 inch long. How many times longer is an average ant than an average aph

id?

1 answer:

ValentinkaMS [17]2 years ago

3 0

3/4 longer than the aphid

You might be interested in

Help me with this!! Will mark Brainliest

tatiyna

Answer:

TU = 19 cm

coz both the triangles are same.

6 0

2 years ago

What is the difference in simplest form? <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bn%5E2%2B3n%2B2%7D%7Bn%5E2%2B6n%2B8%7D-%5

Paha777 [63]

$\bf \cfrac{n^2+3n+2}{n^2+6n+8}-\cfrac{2n}{n+4}\implies \cfrac{n^2+3n+21}{(n+4)(n+2)}-\cfrac{2n}{n+4}
\\\\\\
\textit{so our LCD will just be (n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~(n+2)(2n)}{(n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~(2n^2+4n)}{(n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~2n^2-4n}{(n+4)(n+2)}
\implies 
\cfrac{-n^2-n+2}{(n+4)(n+2)}
\\\\\\
\cfrac{-(n^2+n-2)}{(n+4)(n+2)}\implies \cfrac{-\underline{(n+2)}(n-1)}{(n+4)\underline{(n+2)}}\implies \cfrac{-(n-1)}{n+4}\implies \cfrac{1+n}{n+4}$

3 0

2 years ago

What is the product of z1 and z2 if

MaRussiya [10]

Answer:

308[cos(45) + isin(45)]

Step-by-step explanation:

z1×z2:

Modulus: r1 × r2

= 7×44 = 308

Argument: theta1 + theta2

= -70 + 115 = 45

z1z2 = 308[cos(45) + isin(45)]

Or

z1z2 = 154sqrt(2) + (i)154sqrt(2)

sqrt: square root

8 0

3 years ago

Find the sum of the following

Arisa [49]

1) 23
2) -20
3) 2
4) -28
5) -11

6 0

2 years ago

Please Help Me ASAP I Need <br> This For My grade

mel-nik [20]

Answer:

$\huge slope \: of \: the \: graph = \tan( \alpha ) = \frac{perpendicular}{base} = \frac{(value\:of\: y-axis)}{(value\:of\:x-axis)} = \frac{1}{ - 1} = - 1$

<h2>-1 is the right answer.</h2>

5 0

2 years ago