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Hunter-Best [27]
3 years ago
11

I need help with this problem?

Mathematics
1 answer:
jenyasd209 [6]3 years ago
4 0
The sum of angles of a triangle is 180°.
  (y +10) +(2y) +50 = 180
  3y + 60 = 180
  3y = 120
  y = 40

The appropriate choice is ...
  B. 40°
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A school purchases calculators from a store for six dollars each. Create an equation that represents the total cost, use d for d
Rasek [7]

Answer:

Step-by-step explanation:

6c x 6d= 36d

7 0
3 years ago
Read 2 more answers
The price of a tablet was increased from $180 to $207. What was the percent of increase?
Fudgin [204]

Answer:

15%

Step-by-step explanation:

The price of the tablet was increased from $180 to $207.

Increase = $207 - $180

= $27

Therefore,

Percentage increase = increase/initial amount x 100%

That’s $27/$180 x 100%

0.15 x 100

15%

The percentage increase was 15%

6 0
3 years ago
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In a survey of 1000 eligible voters selected at random, it was found that 100 had a college degree. Additionally, it was found t
o-na [289]

Answer:

A. 8%

B. 39.6%

C. 58.4%

D. 41.6%

Step-by-step explanation:

Computation to determine the probability of eligible voter selected at random

First step is to Draw up a contingincy table which will include Rows = Degree/No degree

and Columns= Vote/Not vote

..............Vote..No vote

Degree 80...20...100

(80%*100=80)

(100-80=20)

No Degree 504..396..900

(1000-100=900)

(56%*900=504)

(504-900=396

Totals 584..416...1000

(80+504=584)

(20+396=416)

(900+100=1,000)

Summary

..............Vote..No vote

Degree 80...20...100

No Degree 504..396..900

Total Totals 584..416...1000

A. Calculation to determine the probability of The voter had a college degree and voted in the last presidential election.

P = 80/1,000

P=0.08*100

P=8%

Therefore the probability of The voter had a college degree and voted in the last presidential election will be 8%

B. Calculation to determine the probability of The voter did not have a college degree and did not vote in the last presidential election.

P =396/1000

P=0.396*100

P=39.6%

Therefore the probability of The voter did not have a college degree and did not vote in the last presidential election will be 39.6%

C. Calculation to determine the probability if The voter voted in the last presidential election.

P = 584/1,000

P=0.584*100

P=58.4%

Therefore the probability if The voter voted in the last presidential election will be 58.4%

D. Calculation to determine the probability if The voter did not vote in the last presidential election.

P = 416/1000

P=0.416*100

P=41.6%

Therefore the probability if The voter did not vote in the last presidential election will be 41.6%

8 0
3 years ago
What is 5g6 in verbal expression
AVprozaik [17]

Step-by-step explanation:

I don't know if this is what you mean but 5 multiplied by g multiplied for 6

5 0
3 years ago
Read 2 more answers
Determine whether the statement is true or false, and explain why.
Zielflug [23.3K]

Answer:

False

Step-by-step explanation:

In this case, i woudnt reccomend to use integration by parts, becuase you are not simplifying the expression by doing an integration and a derivation. It is not easy to integrate 1/x³+1, and if you derivate it, then a natural logarithm would appear, and the integral wont be easier after this parts step.

It is a better idea to use integration by substitution. Note that if you replace x³+1 by a variable y, we have that dy = 3x² dx. We can easily make a 3xdx appear in the integral by multiplying and dividing by 3, solving the integral easily:

\int\limits_0^1 x^2/x^3+1 \, dx = 1/3 * \int\limits_1^2 du/u = (ln(2) - ln(1) )/3

(Note that, if x ranges from 0 to 1, then u = x³+1 ranges from 0³+1 = 1 to 1³+1 = 2)

4 0
3 years ago
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