The solution to the given system of equations is x = -2, y = 5/3. That is (-2, 5/3)
<h3>Solving system of equations </h3>
From the question, we are to determine the solution to the given system of equations
The given system of equation is
y = 2/3 x + 3 ----------- (1)
x= -2 ----------- (2)
The value of x has been given in the second equation of the system of equations.
Now, we will determine the value of y
From the second equation, we have that
x = -2
Substitute the value of x into the first equation,
y = 2/3 x + 3
y = 2/3 (-2) + 3
y = -4/3 + 3
y = 5/3
Hence, the solution to the given system of equations is x = -2, y = 5/3. That is (-2, 5/3)
Learn more on Solving system of equations here: brainly.com/question/13729904
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Answer:
3.7m/s^2
Step-by-step explanation:
T is given as 3.27 seconds
L= 1m
we have to find g just put values in given formula
3.27s=2pi(sqrt(1m/g))
3.27s/2pi=(sqrt(1m/g))
0.520s=(sqrt(1m/g))
Taking square on both side to eliminate square root
0.27085s^2=1m/g
Multiply with g on both sides
0.27085 s^2*g=1m
Divide both sides with 0.27085
g=1m/0.27085s^2
g=3.7m/s^2
Answer:
15.6.
Step-by-step explanation:
5-44• (-0.75) - 18 ÷ 2/3 • 0.8 + (-4/5)
= 5 + 33 - 27*0.8 - 0.8
= 5 + 33 -21.6 - 0.8
= 15.6.
The domain is the set of all possible x-values which will make the function "work", and will output real y-values

there is not a value for x, that makes the function does not "work", so x can take any value, in other words all real numbers
so, the answer is all real numbers
V=LWH
cube
V=L^3
if it is doubled, then each dimention (LWH) is dobubled
since L=W=H
V=(2L)^3
V=8L^3
compared to orignal
L^3 vs 8L^3 it is 8 times more
demonstarte
10^3=1000
5^3=125
1000/125=8, not 2