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mestny [16]
3 years ago
11

Which of the following allows you to view and access important information about your document all in one location?

Computers and Technology
2 answers:
Delvig [45]3 years ago
5 0
The Menu bar allows you to view and access important information about your document all in one location
Dafna1 [17]3 years ago
3 0
The menu bar on your computer would allow you to see everything on the taskbar etc. all at one time. 

Answer: Menu bar
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The new software organization requires a new point of sale and stock control system for their many stores throughout Pakistan to
FrozenT [24]

Answer:

hdyfhwjhsucndiskfbvienucuit

7 0
3 years ago
Assume the availability of a function named oneMore. This function receives an integer and returns one more than its parameter.
jek_recluse [69]

Answer:

oneMore(oneMore(oneMore(oneMore(oneMore(0)))))

Explanation:

  • As a function has been explained which when given an integer results as a next integer. oneMore(given-integer)= next integer
  • As we are restricted to use 0 only and can't use operators like + - * /.
  • We have to obtain a value 5
  • So doing step-by-step:

             (oneMore(0))=1

             (oneMore(oneMore(0)))=2

             (oneMore(oneMore(oneMore(0))))=3

             (oneMore(oneMore(oneMore(oneMore(0)))))=4

             oneMore(oneMore(oneMore(oneMore(oneMore(0)))))=5

7 0
3 years ago
Write a function called 'game_of_eights()' that accepts a list of numbers as an argument and then returns 'True' if two consecut
MrRa [10]

Answer:

In Python:

def main():

   n = int(input("List items: "))

   mylist = []

   for i in range(n):

       listitem = input(", ")

       if listitem.isdecimal() == True:

           mylist.append(int(listitem))

       else:

           mylist.append(listitem)

   print(game_of_eights(mylist))

def game_of_eights(mylist):

   retVal = "False"

   intOnly = True

   for i in range(len(mylist)):

       if isinstance(mylist[i],int) == False:

           intOnly=False

           retVal = "Please, enter only integers"

       if(intOnly == True):

           for i in range(len(mylist)-1):

               if mylist[i] == 8 and mylist[i+1]==8:

                   retVal = "True"

                   break

   return retVal

if __name__ == "__main__":

   main()

Explanation:

The main begins here

def main():

This gets the number of list items from the user

   n = int(input("List items: "))

This declares an empty list

   mylist = []

This iterates through the number of list items

   for i in range(n):

This gets input for each list item, separated by comma

       listitem = input(", ")

Checks for string and integer input before inserting item into the list

<em>        if listitem.isdecimal() == True:</em>

<em>            mylist.append(int(listitem))</em>

<em>        else:</em>

<em>            mylist.append(listitem)</em>

This calls the game_of_eights function

   print(game_of_eights(mylist))

The game_of_eights function begins here

def game_of_eights(mylist):

This initializes the return value to false

   retVal = "False"

This initializes a boolean variable to true

   intOnly = True

This following iteration checks if the list contains integers only

   for i in range(len(mylist)):

If no, the boolean variable is set to false and the return value is set to "integer only"

<em>        if isinstance(mylist[i],int) == False:</em>

<em>            intOnly=False</em>

<em>            retVal = "Please, enter only integers"</em>

This is executed if the integer contains only integers

       if(intOnly == True):

Iterate through the list

           for i in range(len(mylist)-1):

If consecutive 8's is found, update the return variable to True

<em>                if mylist[i] == 8 and mylist[i+1]==8:</em>

<em>                    retVal = "True"</em>

<em>                    break</em>

This returns either True, False or Integer only

   return retVal

This calls the main method

if __name__ == "__main__":

   main()

7 0
3 years ago
Which element is located on the top left of the Word screen?
victus00 [196]
The <span>element located on the top left of the Word screen is the Quick Access Toolbar.  </span>On the quick access toolbar, you can find some of the common functions that you will need to use on a regular basis, it contains commands that are used most often, for example Redo, Undo and Save etc.
7 0
3 years ago
Note: You can use a word document to write your answers and copy-paste your answer to the area specified. a. (5 points) Convert
MrMuchimi

Answer:

EA9_{16} = 3753

CB2_{16} = 3250

(1011 1110 1101 1011 1010)_2 = 781754

(1010 1000 1011 1000 1110 1101)_2 = 11057389

(1011 1110 1101 1011 1010)_2 = BEDBA

(1010 1000 1011 1000 1110 1101)_2 =  A8B8ED

74510_8= 221416

67210_8 = 203212

Explanation:

Solving (a): To base 10

(i)\ EA9_{16

We simply multiply each digit by a base of 16 to the power of their position.

i.e.

EA9_{16} = E * 16^2 + A * 16^1 + 9 * 16^0

EA9_{16} = E * 256 + A * 16 + 9 * 1

In hexadecimal

A = 10; E = 14

So:

EA9_{16} = 14 * 256 + 10 * 16 + 9 * 1

EA9_{16} = 3753

(ii)\ CB2_{16}

This gives:

CB2_{16} = C * 16^2 + B * 16^1 + 2 * 16^0

CB2_{16} = C * 256 + B * 16 + 2 * 1

In hexadecimal

C = 12; B =11

So:

CB2_{16} = 12 * 256 + 11 * 16 + 2 * 1

CB2_{16} = 3250

Solving (b): To base 10

(i)\ (1011 1110 1101 1011 1010)_2

We simply multiply each digit by a base of 2 to the power of their position.

i.e.

(1011 1110 1101 1011 1010)_2 = 1 * 2^{19} + 0 * 2^{18} + 1 * 2^{17} + 1 * 2^{16} +1 * 2^{15} + 1 * 2^{14} + 1 * 2^{13} + 0 * 2^{12} + 1 * 2^{11} + 1 * 2^{10} + 0 * 2^9 + 1 * 2^8 +1 * 2^7 + 0 * 2^6 + 1 * 2^5 + 1 * 2^4 + 1 * 2^3 + 0 * 2^2 + 1 * 2^1 + 0 * 2^0

(1011 1110 1101 1011 1010)_2 = 781754

(ii)\ (1010 1000 1011 1000 1110 1101)_2

(1010 1000 1011 1000 1110 1101)_2 = 1 * 2^{23} + 0 * 2^{22} + 1 * 2^{21} + 0 * 2^{20} +1 * 2^{19} + 0 * 2^{18} + 0 * 2^{17} + 0 * 2^{16} + 1 * 2^{15} + 0 * 2^{14} + 1 * 2^{13} + 1 * 2^{12} +1 * 2^{11} + 0 * 2^{10} + 0 * 2^9 + 0 * 2^8 + 1 * 2^7 + 1 * 2^6 + 1 * 2^5 + 0 * 2^4 + 1*2^3 + 1 * 2^2 + 0 * 2^1 + 1 * 2^0

(1010 1000 1011 1000 1110 1101)_2 = 11057389

Solving (c): To base 16

i.\ (1011 1110 1101 1011 1010)_2

First, convert to base 10

In (b)

(1011 1110 1101 1011 1010)_2 = 781754

Next, is to divide 781754 by 16 and keep track of the remainder

781754/16\ |\ 48859\ R\ 10

48859/16\ |\ 3053\ R\ 11

3053/16\ |\ 190\ R\ 13

190/16\ |\ 11\ R\ 14

11/16\ |\ 0\ R\ 11

Write out the remainder from bottom to top

(11)(14)(13)(11)(10)

In hexadecimal

A = 10; B = 11; C = 12; D = 13; E = 14; F = 15.

(11)(14)(13)(11)(10)=BEDBA

So:

(1011 1110 1101 1011 1010)_2 = BEDBA

ii.\ (1010 1000 1011 1000 1110 1101)_2

In b

(1010 1000 1011 1000 1110 1101)_2 = 11057389

Next, is to divide 11057389 by 16 and keep track of the remainder

11057389/16\ |\ 691086\ R\ 13

691086/16\ |\ 43192\ R\ 14

43192/16\ |\ 2699\ R\ 8

2699/16\ |\ 168\ R\ 11

168/16\ |\ 10\ R\ 8

10/16\ |\ 0\ R\ 10

Write out the remainder from bottom to top

(10)8(11)8(14)(13)

In hexadecimal

A = 10; B = 11; C = 12; D = 13; E = 14; F = 15.

(10)8(11)8(14)(13) = A8B8ED

So:

(1010 1000 1011 1000 1110 1101)_2 =  A8B8ED

Solving (d): To octal

(i.)\ 74510

Divide 74510 by 8 and keep track of the remainder

74510/8\ |\ 9313\ R\ 6

9313/8\ |\ 1164\ R\ 1

1164/8\ |\ 145\ R\ 4

145/8\ |\ 18\ R\ 1

18/8\ |\ 2\ R\ 2

2/8\ |\ 0\ R\ 2

Write out the remainder from bottom to top

74510_8= 221416

(ii.)\ 67210

Divide 67210 by 8 and keep track of the remainder

67210/8\ |\ 8401\ R\ 2

8401/8\ |\ 1050\ R\ 1

1050/8\ |\ 131\ R\ 2

131/8\ |\ 16\ R\ 3

16/8\ |\ 2\ R\ 0

2/8\ |\ 0\ R\ 2

Write out the remainder from bottom to top

67210_8 = 203212

8 0
3 years ago
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