The one line of symmetry is vertical, so we could fold the hexagon in half in such a way that the vertices A and B would meet at the same point, and the same goes for the pairs C,F and D,E. Because of this symmetry, we know angle AFE is congruent to BCD, and angle FED is congruent ot CDE.
Let <em>x</em> be the measure of angle CDE.
In any convex polygon with <em>n</em> sides, the interior angles sum to (<em>n</em> - 2)*180º in measure. ABCDEF is a hexagon, so <em>n</em> = 6.
We have 2 angles of measure 123º, 2 of measure <em>x</em>, and 2 of measure 2<em>x</em>. So
2(123º + <em>x</em> + 2<em>x</em> ) = (6 - 2)*180º
246º + 2<em>x</em> + 4<em>x</em> = 720º
6<em>x</em> = 474º
<em>x</em> = 79º
Angle AFE is congruent to angle BCD, which is twice the measure of CDE, so angle AFE has measure 2*79º = 158º.
<span>When you multiply numbers, two negative signs cancel each other out. Therefore if four of the numbers are negative the product is positive. If either one or three numbers are negative, the product is negative.
1.a negative, b positive, c positive, d positive
2.a positive, b negative, c positive, d positive
3.a positive, b positive, c negative, d positive
4.a positive, b positive, c positive, d negative
5.a positive, b negative, c negative, d negative
6.a negative, b positive, c negative, d negative
7.a negative, b negative, c positive, d negative
8.a negative, b negative, c negative, d positive</span>
1/3 times area of base times height
1/3 x (11x7) x 8
1/3 x 77 x 8
Answer is approximately 205.3
<h2>
Brainiest if I'm correct, thanks!</h2>
1. the number five plus x
2. the number five minus x
3. five times x
4. five divided by x
5. three-forths of x plus two
6. two minus three-forths of x
7. three times x plus ten
8. ten times x plus three