Cos θ = -3/5; θ is in QIII. What is sin θ?
4/5
-5/3
-4/5
5/3
1 answer:
Hello :
<span>Cos θ = -3/5
sin</span>θ = - 4/5
because : Cos² θ +sin²θ = (-3/5)²+(-4/5)2 =9/25+16/25 = 25/25 = 1
and θ is in QIII.where : sinθ <span>< 0</span>
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