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Dima020 [189]
3 years ago
6

You are a network administrator for a large bagel manufacturer that has 32 bakeries located throughout the United States, United

Kingdom, and Switzerland. It is one year after you designed and implemented DHCP for IPv4, and now you must design and implement a DHCPv6 solution for an IPv6 rollout. Because you have a DHCP services system in place, what are the key components that must be researched to verify whether the current infra- structure will support the IPv6 projec
Computers and Technology
1 answer:
Anni [7]3 years ago
4 0

Answer:

See the components in explaination

Explanation:

In order to make it as IPv6, few key components should be supported, those components are given below:

The infrastructure must support the enhanced protocol StateLess Address Auto-Configuration (SLAAC).

Static addressing with DHCPv6, dynamic addressing with DHCPv6 and SLAAC are the methods used to configure the IPv6. The network administrator should able to understand and implement the IPv6 through the DHCPv6.

Other than the implementation, working of IPv4 and IPv6 are same. Therefore, the administrator need not to learn new information for its working.

As the IPv6 address length is 128-bit and purpose is for everything on line to have an IP address. It must allow the internet to expand faster devices to get internet access quickly.

The DHCPv6 is not supported by all windows. Therefore, network administrator should check the corresponding Operating system (OS) would support the DHCPv6 for IPv6.

The network administrator must have good knowledge and skills on the IPv6.

The above mentioned key components should be verified by the network administrator in order to support for IPv6 project with DHCPv6.

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"Switches break up _______________ domains and routers break up _____________ domains."
mel-nik [20]

Answer:

Switches break up collision domains and routers break up broadcast domains.

Explanation:

  • Collision domain depicts the part within a network where a collision can happen.
  • Collision occurs when two hosts transmit data packet at the same time within a network. Theses packets collide and the hosts have to resend the data after some time.
  • Too many collisions can result in slow traffic speed and can effect network performance.
  • So switches break up collision domains between the devices on a network and each port in a switch depicts a collision domain. This reduces the chance of packet collisions between the devices or hosts.
  • When data is to be sent to a host, the switch keeps that data frame and waits for availability of the destination host before sending the data frame.
  • Moreover full duplex switch mode there is not chance of collision as the transmitting path on one host is the receiving path on other host.
  • Broadcast domain contains all the hosts that can reach each other at the Data Link layer via broadcast.
  • Routers break up broadcast domains as routers contain separate broadcast domains for each interface.
  • Routers do not forward broadcasts from one broadcast domain to other and drop the packet when they detect a broadcast address.
4 0
3 years ago
What is the answer for 2.8.10 word games? This is what I have so far, but I can’t seem to be able to figure out the bananaSplit
Feliz [49]

Answer:

 public String bananaSplit(int insertIdx, String insertText) {

     return word.substring(0, insertIdx) + insertText + word.substring(insertIdx);

 }

Explanation:

Do you have the other parts of the WordGames class?

8 0
3 years ago
In some video games, the player cannot obtain the reward without doing what with something that they already have?
Crank

Answer:

risking

Explanation:

8 0
3 years ago
Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r
kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

  INVOKE Str_find,ADDR target, ADDR source

  mov position,eax

  jz wasfound           ; ZF=1 indicates string found

  mov edx,OFFSET str3   ; string not found

  call WriteString

  jmp   quit

wasfound:                   ; display message

  mov edx,OFFSET str1

  call WriteString

  mov eax,position       ; write position value

  call WriteDec

  mov edx,OFFSET str2

  call WriteString

quit:

  exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

;    to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

  INVOKE Str_length,pTarget   ; get length of target

  mov lenTarget,eax

  INVOKE Str_length,pSource   ; get length of source

  mov lenSource,eax

  mov edi,OFFSET target       ; point to target

  mov esi,OFFSET source       ; point to source

; Compute place in target to stop search

  mov eax,edi    ; stop = (offset target)

  add eax,lenTarget    ; + (length of target)

  sub eax,lenSource    ; - (length of source)

  inc eax    ; + 1

  mov stop,eax           ; save the stopping position

; Compare source string to current target

  cld

  mov ecx,lenSource    ; length of source string

L1:

  pushad

  repe cmpsb           ; compare all bytes

  popad

  je found           ; if found, exit now

  inc edi               ; move to next target position

  cmp edi,stop           ; has EDI reached stop position?

  jae notfound           ; yes: exit

  jmp L1               ; not: continue loop

notfound:                   ; string not found

  or eax,1           ; ZF=0 indicates failure

  jmp done

found:                   ; string found

  mov eax,edi           ; compute position in target of find

  sub eax,pTarget

  cmp eax,eax    ; ZF=1 indicates success

done:

  ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0
3 years ago
To freeze rows 1 and 2, and columns 1, 2, and 3, which cell should you highlight before selecting freeze panes?.
Brilliant_brown [7]

In the case above, the cell that you can highlight before selecting freeze panes is row 3 column 4.

<h3>How do one freeze several column?</h3>

This can be done when a person select the column that's is said to be next to the right of the last column a person want to freeze.

Therefore, In the case above, the cell that you can highlight before selecting freeze panes is row 3 column 4.

Learn more about panes from

brainly.com/question/17194167

#SPJ1

4 0
2 years ago
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