If you’re using the inspection method, what constant term would you need in the numerator of this rational expression for (x+5) to be a common factor? (x^2+6x+14) / (x+5)
2 answers:
Answer with explanation:
We want , (x+5) to be a Common factor of the rational expression
So, if we write
x^2+6 x+14=x²+6 x+ 5+9
So, to get (x+5) as a common factor, we should subtract 9 from the Quadratic expression.
⇒Subtract ,9 from the Numerator,That is constant term that we need in Numerator = -9
<span>If I am using the inspection method, the constant term that I would need in the numerator of this rational expression for (x+5) to be a common factor of (x^2+6x+14) / (x+5) is 11/(x+1)</span>
You might be interested in
50 and 50 because half of 100 is 50 and 50
The answer i thinkkk would be, x < -1
Answer:
8y=8 or 4y=-4
Step-by-step explanation:
1.)-2(x+3y=-1)
2x+2y=6
2.)-2x+6y=2
2x+2y=6
3.)6y=2
2y+6
4.)8y=8 (If adding) or 4y=-4 (If subtracting)
What was the point of this?